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ira [324]
3 years ago
5

The trunk of a tree is 50 cm thick. Each year it gets thicker by 1 cm . How thick will the tree trunk be in 50 years?

Mathematics
2 answers:
vovangra [49]3 years ago
7 0

Answer:

100cm

Step-by-step explanation:

It starts at 50cm.

Each year you're adding 1cm.

1cm*50 years = 50cm

50+50=100

Korolek [52]3 years ago
4 0
It’s already 50cm and it grows 1 cm each year, so 1cm times 50 years =50cm plus the other 50=100cm
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Gnom [1K]

Answer:

<u>S': (2, 1)</u>

<u>T': (5, 3)</u>

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<u>S'': (1, 3)</u>

<u>T'': (4, 5)</u>

<u>U'': (0, -2)</u>

Step-by-step explanation:

Hi!

For Reflection Across the X-Axis use this :

(x, y) -> (x, - y)

So :

S': (2, 1)

T': (5, 3)

U': (1, -4)

and then the question also asks for a translation so we follow what it gave us:

S'': (1, 3)

T'': (4, 5)

U'': (0, -2)

Please ask me any questions that you still may have!

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5 0
1 year ago
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never [62]

9514 1404 393

Answer:

  x = 8

Step-by-step explanation:

By AA similarity, ΔABD ~ ΔCDE. So, corresponding sides are proportional.

  AB/BD = CD/DE

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5 0
3 years ago
Which expression represents the difference (4b+7)−(6b−3)? show your work..
Zina [86]

Answer:

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Step-by-step explanation:

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4b + 7 - 6b + 3

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5 0
3 years ago
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4 years ago
If $10,000 is invested at an annual rate of 11%, compounded quarterly, find the value of the investment after the given number o
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Answer:

a) A\simeq17204.28

b) A\simeq29598.74

c)A\simeq50922.51

Step-by-step explanation:

The amount formula in compound interest is:

A=P(1+\frac{r}{n} )^{nt}

where:

P = principal amount

r = annual interest

n = number of compounding periods

t = number of years

We already know that:

P = $10000

r = 11\% = \frac{11\%}{100\%}=0.11

n = 4 (quarterly in a year)

a ) t = 5 years

A=10000(1+\frac{0.11}{4} )^{(4)(5)}\\\\A=10000(1+\frac{0.11}{4} )^{20}\\\\A=17204.28431\\\\A\simeq17204.28

b) t = 10 years

A=10000(1+\frac{0.11}{4} )^{(4)(10)}\\\\A=10000(1+\frac{0.11}{4} )^{40}\\\\A=29598.73987\\\\A\simeq29598.74

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3 years ago
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