Answer:
![\displaystyle a:b=\frac{1}{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20a%3Ab%3D%5Cfrac%7B1%7D%7B3%7D)
Step-by-step explanation:
<u>Ratios
</u>
We are given the following relations:
![a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]](https://tex.z-dn.net/?f=a%3D%5Csqrt%7B7%7D%2B%5Csqrt%7Bc%7D%5Cqquad%20%5Cqquad%5B1%5D)
![b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B63%7D%2B%5Csqrt%7Bd%7D%5Cqquad%20%5Cqquad%5B2%5D)
![\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bc%7D%7Bd%7D%3D%5Cfrac%7B1%7D%7B9%7D%20%5Cqquad%20%5Cqquad%20%5B3%5D)
From [3]:
![9c=d](https://tex.z-dn.net/?f=9c%3Dd)
Replacing into [2]:
![b=\sqrt{63}+\sqrt{9c}](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B63%7D%2B%5Csqrt%7B9c%7D)
We can express 63=9*7:
![b=\sqrt{9*7}+\sqrt{9c}](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B9%2A7%7D%2B%5Csqrt%7B9c%7D)
Taking the square root of 9:
![b=3\sqrt{7}+3\sqrt{c}](https://tex.z-dn.net/?f=b%3D3%5Csqrt%7B7%7D%2B3%5Csqrt%7Bc%7D)
Factoring:
![b=3(\sqrt{7}+\sqrt{c})](https://tex.z-dn.net/?f=b%3D3%28%5Csqrt%7B7%7D%2B%5Csqrt%7Bc%7D%29)
Find the ration a:b:
![\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20a%3Ab%3D%5Cfrac%7B%5Csqrt%7B7%7D%2B%5Csqrt%7Bc%7D%7D%7B3%28%5Csqrt%7B7%7D%2B%5Csqrt%7Bc%7D%29%7D)
Simplifying:
![\boxed{a:b=\frac{1}{3}}](https://tex.z-dn.net/?f=%5Cboxed%7Ba%3Ab%3D%5Cfrac%7B1%7D%7B3%7D%7D)
192 minutes or 3 hours and 12 minutes
an hour is 60 minutes and 60 divided by five is 12 so i multiplied 12 by 4, which is 48 and multiplied 48 by 4 and i got my answer
Your answer is 94/15
if mixed, it’s 6 4/15
Problem:
The area of the patio of a relative's house is 20 square meters.
The width of the patio is 2 meters.
What is the length of the patio?
Solution:
The area is:
A = (w) * (l)
Where,
w: width
l: long
Clearing l we have:
l = A / w
Substituting values:
l = 20/2
l = 10 meters
Answer:
I think thr answer mughr ve B for what it sais