Answer:
The smallest positive integer solution to the given system of congruences is 30.
Step-by-step explanation:
The given system of congruences is


where, m and n are positive integers.
It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as



Now, we can say that m>n because m and n are positive integers.
For n=1,


19 is not divisible by 5 so m is not an integer for n=1.
For n=2,



The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is

Therefore the smallest positive integer solution to the given system of congruences is 30.
Answer:
a2 (10x10) + b2 (4x4) = c2 (100+16)
Answer: √116
Omg I’m stuck on a question like that and I made another account and posted it there and nobody is answer me
Answer:
The answer is A
Step-by-step explanation:
10 divided by 5
Answer:
x^3 - 2x^2 + 9x - 18.
Step-by-step explanation:
The complex roots occur in conjugate pairs so there are 3 roots 2, 3i and -3i.
So we have:
P(x) = (x - 2)(x - 3i)(x + 3i)
= (x - 2)(x^2 - 9i^2)
= (x - 2)(x^2 - 9*-1)
= (x - 2)(x^2 + 9)
= x^3 + 9x - 2x^2 - 18
= x^3 - 2x^2 + 9x - 18.