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2 years ago

What’s the correct answer

Mathematics

1 answer:

ElenaW [278]2 years ago

7 0

Answer:about 13

Step-by-step explanation:because when the line hits 100 on the y axis, it hits somewhere around 13 on the x axis.

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Solve for : x 4(x+5)=3(x-2)-2(x+2)

Allushta [10]

Hey there!!

In order to solve this equation, we will have to use the distributive property.

What is distributive property?

We will need to distribute one term to the other terms preset.

Example : 4 ( 3x - 1 )

sing distributive property, we will have to distribute the term outside the parenthesis to the terms inside. In this case, we will have to distribute 4 to 3x and -1

( 4 × 3x ) + ( 4 × -1 )

12x + ( -4 )

= 12x - 4

This is after implementing the distributive property.

Now moving back onto the question

4 ( x + 5 ) = 3 ( x - 2 ) - 2 ( x + 2 )

Let us first solve 4 ( x + 5 )

Distribute 4 to x and 5

( 4 × x ) + ( 4 × 5 )

4x + 20

Now let's solve 3 ( x - 2 )

Distribute 3 to x and -2

( 3 × x ) + ( 3 × - 2 )

3x - 6

Solve for -2 ( x + 2 )

Distribute -2 to x and 2

( -2 × x ) + ( -2 × 2 )

-2x - 4

Now, let's get everything back together

4x + 20 = 3x - 6 - 2x - 4

Combine all the like terms

4x + 20 = x - 10

Adding 10 on both sides

4x + 20 + 10 = x - 10 + 10

4x + 30 = x

Subtracting 4x on both sides

4x - 4x + 30 = x - 4x

30 = -3x

Dividing by -3 on both sides

30 / -3 = -3x / -3

- 10 = x

<h2>x = - 10 </h2><h3>Hope my answer helps!</h3>

5 0

2 years ago

A trapezoid has an area of 294 square yards. Its height is 14 yards and the length of one base is 30 yards. Find the length of t

nordsb [41]

Your answer is 250 yards you basically just subtract the numbers it gives you from the 294....

5 0

3 years ago

during a promotional event a sporting good store gives a free t-shirt to every 8th customer and a free water bottle to every ten

sergij07 [2.7K]

Find out what number goes into 8 and 10 then figure out how many times that number goes into 100

7 0

3 years ago

37. Verify Green's theorem in the plane for f (3x2- 8y2) dx + (4y - 6xy) dy, where C is the boundary of the

Nastasia [14]

I'll only look at (37) here, since

• (38) was addressed in 24438105

• (39) was addressed in 24434477

• (40) and (41) were both addressed in 24434541

In both parts, we're considering the line integral

$\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy$

and I assume C has a positive orientation in both cases

(a) It looks like the region has the curves y = x and y = x ² as its boundary***, so that the interior of C is the set D given by

$D = \left\{(x,y) \mid 0\le x\le1 \text{ and }x^2\le y\le x\right\}$

• Compute the line integral directly by splitting up C into two component curves,

C₁ : x = t and y = t ² with 0 ≤ t ≤ 1

C₂ : x = 1 - t and y = 1 - t with 0 ≤ t ≤ 1

Then

$\displaystyle \int_C = \int_{C_1} + \int_{C_2} \\\\ = \int_0^1 \left((3t^2-8t^4)+(4t^2-6t^3)(2t))\right)\,\mathrm dt \\+ \int_0^1 \left((-5(1-t)^2)(-1)+(4(1-t)-6(1-t)^2)(-1)\right)\,\mathrm dt \\\\ = \int_0^1 (7-18t+14t^2+8t^3-20t^4)\,\mathrm dt = \boxed{\frac23}$

*** Obviously this interpretation is incorrect if the solution is supposed to be 3/2, so make the appropriate adjustment when you work this out for yourself.

• Compute the same integral using Green's theorem:

$\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy = \iint_D \frac{\partial(4y-6xy)}{\partial x} - \frac{\partial(3x^2-8y^2)}{\partial y}\,\mathrm dx\,\mathrm dy \\\\ = \int_0^1\int_{x^2}^x 10y\,\mathrm dy\,\mathrm dx = \boxed{\frac23}$

(b) C is the boundary of the region

$D = \left\{(x,y) \mid 0\le x\le 1\text{ and }0\le y\le1-x\right\}$

• Compute the line integral directly, splitting up C into 3 components,

C₁ : x = t and y = 0 with 0 ≤ t ≤ 1

C₂ : x = 1 - t and y = t with 0 ≤ t ≤ 1

C₃ : x = 0 and y = 1 - t with 0 ≤ t ≤ 1

Then

$\displaystyle \int_C = \int_{C_1} + \int_{C_2} + \int_{C_3} \\\\ = \int_0^1 3t^2\,\mathrm dt + \int_0^1 (11t^2+4t-3)\,\mathrm dt + \int_0^1(4t-4)\,\mathrm dt \\\\ = \int_0^1 (14t^2+8t-7)\,\mathrm dt = \boxed{\frac53}$

• Using Green's theorem:

$\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dx = \int_0^1\int_0^{1-x}10y\,\mathrm dy\,\mathrm dx = \boxed{\frac53}$

4 0

3 years ago

A palm tree casts a shadow that is 28 feet long. A 6 foot sign casts a shadow that is 8 feet long. How tall is the palm tree? Se

alukav5142 [94]

Answer:

Step-by-step explanation:

28/x=8/6

oopsie if im wrong

4 0

3 years ago