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prisoha [69]
3 years ago
12

[Image: 1 apple, 3 oranges for each of 5 steps on the slider]

Mathematics
1 answer:
Elina [12.6K]3 years ago
6 0
For every 3 apples, there are 6 oranges
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What are all the exact solutions of -3tan^2x+1= 0? Give your answer in radians
lord [1]

Answer:

x = π(n - \frac{1}{6})

Step-by-step explanation:

Find attached Solution

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3 years ago
Cheryl has some oranges. she puts the oranges into p boxes of 3 oranges each and has 2 oranges left. Find the total number of or
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So she had x oranges

she put the oranges into p boxes with 3 in each box and had 2 left so

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starting on day 1 with 1 jumping jack, keila doubles the number of jumping jacks she does every day. How many jumping jack will
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3 years ago
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k0ka [10]

9514 1404 393

Answer:

  1. 6x +y = -6
  2. 6x -y = 8
  3. 5x +y = 13

Step-by-step explanation:

To rewrite these equations from point-slope form to standard form, you can do the following:

  • eliminate parentheses
  • subtract the x-term
  • subtract the constant on the left
  • if the coefficient of x is negative, multiply by -1

Of course, any operation you do must be done <em>to both sides of the equation</em>.

__

1. y -6 = -6(x +2)

  y -6 = -6x -12 . . . . . eliminate parentheses

  6x +y -6 = -12 . . . . . add 6x

  6x +y = -6 . . . . . . . . add 6

__

2. y +2 = 6(x -1)

  y +2 = 6x -6

  -6x +y +2 = -6

  -6x +y = -8

  6x -y = 8 . . . . . . . . multiply by -1

__

3. y -3 = -5(x -2)

  y -3 = -5x +10

  5x +y -3 = 10

  5x +y = 13

_____

<em>Additional comment</em>

The "standard form" of a linear equation is ax+by=c for integers a, b, c. The leading coefficient (generally, 'a') should be positive, and all coefficients should be mutually prime (have no common factors). That is why we multiply by -1 in problem 2.

7 0
3 years ago
Given a = 2i+j – 2k<br> b= -1 – 7j+k<br> Find a x b
castortr0y [4]

Step-by-step explanation:

a = 2i + j - k

b = -1 -7j + k

a × b = (2i + j - k) (-1 + 7j + k)

-2i + 14ij + 2ik - j + 7j^2 + jk + k -7jk - k^2

-2i + 14ij + 2ik -j +7j^2 +jk - 7jk + k - k^2

-2i + 14ij + 2ik - j +7j^2 - 6jk + k - k^2

7 0
3 years ago
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