Answer:
9.7 , 310.4
Step-by-step explanation:
length of each side = 64/8=8
using theorem Pythagoras
A²=10.5² – (8/2)²
A=9.7 ft
area of triangle
1/2×8×9.7=38.8
area of octagon
38.8×8=310.4
Answer:
Step-by-step explanation:
1. Move the 6 to the other side: x^2 +4x =6
2. Square half the coefficient of the x term: (4/2)^2 = 4
3. Add this 4, and then subtract this 4, from x^2 + 4x:
x^2 +4x + 4 - 4 =6
4. Rewrite this perfect square as the square of a binomial:
(x + 2)^2 - 4 = 6
5. Add 4 to both sides: (x + 2)^2 = 10
6. Find the sqrt of both sides: x + 2 = √
The minimum value for 2x is 0
<span>the maximum value is achieved when A, D and C are collinear and the quadrilateral ABCD becomes an isosceles triangle ABC </span>
<span>base AB = 52 and vertical angle 2x + 34° </span>
<span>For the sine law </span>
<span>(sin 2x)/22 = (sin ADB)/AB </span>
<span>(sin 34°)/30 = (sin BDC)/BC </span>
<span>is given that AB = BC, and sin ADC = sin BDC because they are supplementary, so from </span>
<span>(sin ADC)/AB = (sin BDC)/BC </span>
<span>it follows </span>
<span>(sin 2x)/22 = (sin 34°)/30 </span>
<span>sin 2x = 22 (sin 34°)/30 </span>
<span>2x = asin(22 (sin 34°)/30) ≈ 24.2° </span>
<span>x = 0.5 asin(22 (sin 34°)/30) ≈ 12.1° </span>
<span>0 < x < 12.1°</span>
