SA=2pir^2+2hpir=2pir(r+h)
h=2r=2(2x+3)=4x+6
SA=2pi(2x+3)(2x+3+4x+6)
SA=(4x+6)(pi)(6x+9)
SA=24πx²+27πx+54π
Answer: She has 21 lira coins.
Step-by-step explanation:
Given, Laura collects old foreign coins. She has 83 coins in total. She has 53 lira and drachma coins. She has 51 lira and peseta coins.
Let x = the number of lira coins.
y= the number of drachma coins.
z= the number of peseta coins.
Then, as per given, we have
x+y+z=83 (i)
x+y=53 (ii)
x+z=51 (iii)
From (ii) and (iii)
y=53-x
z=51-x
Put these values in (i) , we get
x+(53-x)+(51-x)=83
⇒ x+53-x+51-x=83
⇒ 104-x=83
⇒104-83=x
⇒x= 21
Hence, she has 21 lira coins.
Answer:
x = -7
Step-by-step explanation:
4 - 2(x - 3) = 24
Subtract 4 from each side
4-4 - 2(x - 3) = 24-4
-2(x-3) = 20
Divide each side by -2
-2(x-3)/-2 = 20/-2
x-3 = -10
Add 3 to each side
x-3+3 = -10+3
x = -7
Answer:
D
Step-by-step explanation:
Linear equation should not have any power, or fractions
