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Likurg_2 [28]
3 years ago
10

A tin of baked beans costs 42p. Its price increases by 9% over the next 12 months. How much

Mathematics
1 answer:
Talja [164]3 years ago
8 0

Answer:

46p

Step-by-step explanation:

42*1.09=45.78

45.78 rounded up is 46p

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Identify the slope and y-intercept of the<br> line!
marta [7]

Slope of the line = \frac{1}{2}.

y-intercept of the line = -7.

Solution:

General form of equation of a line:

y = mx + c

where m is the slope and c is the y-intercept of the line.

Equation of a line:

$y=\frac{1}{2} x-7

To compare this with general equation.

$m=\frac{1}{2}

c=-7

Slope of the line = \frac{1}{2}.

y-intercept of the line = -7.

5 0
3 years ago
A salesman sells an item for $125. He gets a 20% commission. How<br> much money did he make?
My name is Ann [436]

Answer:$25

Step-by-step explanation:

20% of 125 is $25 dollars so his commission would be $25

6 0
3 years ago
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Triangle 2 and triangle 3 were created by drawing an altitude in triangle 1. What is the relationship between the green highligh
Naily [24]

Answer:

Triangle 1 line segment AB and triangle 2 line segment BA correspond to each other

Step-by-step explanation:

Point b and point a don't correspond to anything else

triangle 1 and 2 are congruent my answer would be a 50/50 guess between C and D If it were me id risk it and go D but it is up to you.

4 0
3 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

               Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 2.65

           \sigma  = standard deviation = 0.85

            n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

    P(X bar <= 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{3-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z < 2.06) = 0.98030

 P(X bar <= 2.65) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } } ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3)  = 0.98030 - 0.5 = 0.4803 .

                                                                             

8 0
3 years ago
One night a theater sold 186 movie tickets. an adults ticket cost $14, and a childs costs $10. in all, $2148 was taken in. How m
inna [77]

Answer:

72 adult tickets were sold and 114 child tickets were sold.

Step-by-step explanation:

x+y=186, 14x=10y=2148

x=186-y

14(186-y)+10y=2148

2604-14y+10y=2148

2604-4y=2148

-4y=-456

y=144

x=186-144 : x=72

3 0
3 years ago
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