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Airida [17]
4 years ago
13

What is the first month in which Maria's amount of land exceeds Lucia's amount of land?

Mathematics
1 answer:
Kruka [31]4 years ago
5 0

Answer:

7th Month

Step-by-step explanation:

The number of hectares of Lucia's land grows arithmetically by 5 hectares each month.

Whereas, the number of hectares of Maria's land grows geometrically with a common ratio of 1.4 every month.

Writing this as sequence expressions:

For Lucia,

First term, a=11 hectares

Common difference, d=5

Therefore:

T(n)=a+(n-1)d

11+5(n-1)=11+5n-5\\=6+5n

For Maria,

First term, a=6 hectares

Commons ratio=1.4

T(n)=ar^{n-1}\\=6*1.4^{n-1}

Next, we compute and compare the results for values of n of these two equations:

Lucia, T(n)=6+5n

Maria,T(n)=6*1.4^{n-1}

Lucia, T(1)=6+5=11

Maria,T(1)=6*1.4^{1-1}=6

Lucia, T(2)=6+5(2)=16

Maria,T(2)=6*1.4^{2-1}=8.4

Lucia, T(3)=6+5(3)=21

Maria,T(3)=6*1.4^{3-1}=11.76

Lucia, T(4)=6+5(4)=26

Maria,T(4)=6*1.4^{4-1}=16.56

Lucia, T(5)=6+5(5)=31

Maria,T(5)=6*1.4^{5-1}=23.05

Lucia, T(6)=6+5(6)=36

Maria,T(6)=6*1.4^{6-1}=32.27

Lucia, T(7)=6+5(7)=41

Maria,T(7)=6*1.4^{7-1}=45.18

Therefore, in the seventh month, Maria's land will exceed that of Lucia.

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Hii!

____________________________________________________________

\rightsquigarrow\circ\boldsymbol{Answer}\circ\leftharpoonup

2k(1+5a) <em>or </em>2k(5a+1)

\rightsquigarrow\circ\boldsymbol{Explanation.}\circ\leftharpoonup

First of all, let's find the common term of this binomial (an expression with two terms; the prefix bi- means "two")

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\twoheadrightarrow\sf 2k\div2k+10ak\div2k

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\bullet <em>2k can't just vanish into thin air, so we put it outside the parentheses:</em>

<em />\twoheadrightarrow\sf 2k(1+5a)

\bullet <em>Great job! We factored the expression successfully</em>

<em />

<em>--</em>

Hope that this helped! Best wishes.

\textsl{Reach far. Aim high. Dream big.}\\\boldsymbol{-Greetings!-}

--

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A supply company manufactures copy machines. The unit cost C (the cost in dollars to make each copy machine) depends on the numb
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4 0
3 years ago
Read 2 more answers
ALGEBRA 1 HELP!! Andrea buys 4 bags of granola and 3 bags of dried fruit. She spends $51.50. Carter buys 2 bags of granola and 4
timurjin [86]

Answer:

Granola is $6.95/bag and Dried Fruit is $7.90/bag.

Step-by-step explanation:

Let G and F stand for the cost of 1 bag Granola and 1 bag dried Fruit.

We learn that Andrea's total was $51.50.  Her purchase can be written as the sum of the cost of 4 bags granola (4G) and 3 bags fruit (3F):

   4G + 3F = $51.50

We can do the same for Carter:

   2G + 4F = $45.50

We have two equations and two unknowns, so we should be able to solve for both unknowns.  To do this, we need to find a way to eliminate one of the unknows in a single equation.  Let's rearrange Carter's equation to isolate G on one side:

2G + 4F = $45.50

2G  = $45.50 - 4F

G = ($45.50 - 4F)/2

Now use this expression for G in Andrea's equation:

4G + 3F = $51.50

4(($45.50 - 4F)/2) + 3F = $51.50

2($45.50 - 4F) + 3F = $51.50

($91.00 - 8F) + 3F = $51.50

-5F = - $39.5

F = $7.90  <u>One bag of dried fruit is $7.90.</u>

Now use this value for F in either equation for find G:

2G  = $45.50 - 4F

2G  = $45.50 - 4($7.90)

2G = $13.90

G = $6.95   <u>One bag of granola is $6.95</u>

---------------

Check to see if these values work:

<u>Andrea: </u>

4G + 3F = $51.50  :

4($6.95) + 3($7.90) = $51.50  ?

$51.50 = $51.50   <u>YES</u>

<u>Carter:</u>

2G + 4F = $45.50

2($6.95) + 4($7.90) = $45.50  ?

$45.50                     =  $45.50   <u>YES</u>

<u></u>

4 0
3 years ago
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