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Anna [14]
3 years ago
5

Harry measures the big prize wheel on a game show and calculates that it has an area of 12.56 square yards. What is the prize wh

eel diameter?
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
6 0

Answer:

The prize wheel diameter is 4.00 yards

Step-by-step explanation:

Area (A) = πd^2/4

πd^2 = 4A

d^2 = 4A/π

d (diameter) = √(4A/π)

A = 12.56 square yards, π = 3.142

d = √(4×12.56/3.142) = √15.99 = 4.00 yards

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Someone help please.
malfutka [58]

Answer:

$27

Step-by-step explanation:

If the table was marked up 125%, you can find the retail price of it this way:

20 + 1.25(20) = retail price

$45 = retail price.

To find 40% off of that, use

$45 - .4($45) = sale price

$27 = sale price (aka discount price)

5 0
3 years ago
How do u get this?? I know the answer but then I don't know why they shuld divide by 2 I will mark the person who explains wit p
Greeley [361]

Answer:

10.89

Step-by-step explanation:

Circle:

C = TTD

C = TT(6.6)

C = 20.73451151

C = 20.73

Triangle:

A = bh/2

A = 6.6(3.3)/2        6.6/2=3.3

A = 21.78/2

A = 10.89

Shaded Region = 10.89

5 0
3 years ago
What is the solution of this proportion 4/9 = 6/d
Alchen [17]

Answer:

d = 2/27

Remember that when a variable is times with a number you <u>divide</u> the number on both sides.

When a variable is divided by a number, you <u>multiply</u> the number on both sides.

Hope this helps you and thank you !!

4 0
3 years ago
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
Simplify (-2x-3)-(3x²-8x+9) <br>in standard form.
Musya8 [376]
(-2 x -3) - (3x^2 - 8x + 9)
     -6     -    9x - 17x
    -6          -        -8x
              -14x

hope this helps,
Batgirl12
8 0
3 years ago
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