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allochka39001 [22]
3 years ago
6

Captain Ben has a ship, the H.M.S Crimson Lynx. The ship is four furlongs from the dread pirate Umaima and her merciless band of

thieves.
If his ship hasn't already been hit, Captain Ben has probability \dfrac{3}{4}
4
3
​
start fraction, 3, divided by, 4, end fraction of hitting the pirate ship. If his ship has been hit, Captain Ben will always miss.
If her ship hasn't already been hit, dread pirate Umaima has probability \dfrac{1}{2}
2
1
​
start fraction, 1, divided by, 2, end fraction of hitting the Captain's ship. If her ship has been hit, dread pirate Umaima will always miss.
If the Captain and the pirate each shoot once, and the pirate shoots first, what is the probability that both the pirate and the Captain hit each other's ships?
Mathematics
1 answer:
IceJOKER [234]3 years ago
3 0

Answer:

0

Step-by-step explanation:

We are told that if the Captain's ship has been hit, he will always miss and since the pirate is shooting first, the captain's ship could be hit. So the probability that both of them hit each other's ship is 0 because if the pirate hits the Captain's ship, he will always miss.  1/2 * 0 = 0

There is no way for both of them to hit each other's ships because if their ships have been hit, they will always miss.

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PLEASE HELP 10pts
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Answer:

Hence the function which has the smallest minimum is: h(x)

Step-by-step explanation:

We are given function f(x) as:

  • f(x) = −4 sin(x − 0.5) + 11

We know that the minimum value attained by the sine function is -1 and the maximum value attained by sine function is 1.

so the function f(x) receives the minimum value when sine function attains the maximum value since the term of sine function is subtracted.

Hence, the minimum value of f(x) is: 11-4=7 ( when sine function is equal to 1)

  • Also we are given a table of values for function h(x) as:

x    y

−2   14

−1   9

 0   6

  1   5

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 3   9

 4   14

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  • Also we are given function g(x) ; a quadratic function passing through (2,7),(3,6) and (4,7)

so, the equation will be:

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Micah was asked to add the following expressions:

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