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dolphi86 [110]
3 years ago
12

What are the solutions to the equation?

Mathematics
1 answer:
Maru [420]3 years ago
6 0

rearrange the equation to where you set it equal to 0 by moving the 25 over.

n2 - 8n -9 = 0

now factor

(n-9)(n+1)

so n1 = 9

n2 = -1

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Carlos and Lily want to know the combined amount of money they made last week. They both made $12 per hour, but Carlos also made
steposvetlana [31]

Answer:

  • Lily is right

Step-by-step explanation:

<u>Carlos made:</u>

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<u>Lily made:</u>

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<u>Together they made:</u>

  • 12C + 35 + 12L = 12(C + L) + 35

Lily is right. We don't know what 120 means in Carlos's equation, he should put 12L for Lily.

6 0
2 years ago
Which equation is equivalent to √x^2+81 = x+10
jeka57 [31]

Keywords:

<em>equation, operations, equivalent, binomial, square root </em>

For this case we have an equation in which we must apply operations to rewrite it in an equivalent way. We must start by raising both sides of the equation to the square. Thus, we eliminate the square root of the left side of equality and finally solve the binomial of the right side of equality.

So we have:

\sqrt {x ^ 2 + 81} = x + 10\\(\sqrt {x ^ 2 + 81}) ^ 2 = (x + 10) ^ 2\\x ^ 2 + 81 = (x + 10) ^ 2

By definition:(a + b) ^ 2 = a ^ 2 + 2ab + b ^ 2

x ^ 2 + 81 = x ^ 2 + 2 (x) (10) + (10) ^ 2\\x ^ 2 + 81 = x ^ 2 + 20x +100

Thus, x ^ 2 + 81 = x ^ 2 + 20x +100 is equivalent to \sqrt {x ^ 2 + 81} = x + 10

Answer:

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Option D

4 0
3 years ago
Read 2 more answers
What is the linear function equation represented by the graph?
alexdok [17]
Slope is 2/3
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8 0
3 years ago
Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
Luda [366]

Answer:

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How many ways are there to select a 5-card hand from a regular deck such that the hand contains at least one card from each suit
Snezhnost [94]

Answer:

There are 685464 ways of selecting the 5-card hand

Step-by-step explanation:

Since the hand has 5 cards and there should be at least 1 card for each suit, then there should be 3 suits that appear once in the hand, and one suit that apperas twice.

In order to create a possible hand, first we select the suit that will appear twice. There are 4 possibilities for this. For that suit, we select the 2 cards that appear with the respective suit. Since there are 13 cards for each suit, then we have {13 \choose 2} = 78 possibilities. Then we pick one card of all remaining 3 suits. We have 13 ways to pick a card in each case.

This gives us a total of 4*78*13³ = 685464 possibilities to select the hand.

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