The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:

Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Replace the second equation y=3x+4 into the first one:
2(3x+4)+5x=30
Now solve for x:
6x+8+5x=30
11x=30-8
11x=22
x=22/11
x=2
Finally, replace x=2 into y=3x+4
y=3*2+4
y=6+4 = 10
So the anwer is x=2, y=10
Answer:
15°
Step-by-step explanation:
The line in the middle of the triangle divides it into two triangles. These two triangles are equal. You can see this because the given angle (90°) is equal for both sides, and the bottom sides (23) are also equal to each other.
Since the triangles are equal, this means that the given angle of 75° also applies to the other side. The total degrees a triangle can have is 180°. Use the given angles to solve for the unknown angle.
75° + 90° + x = 180°
165° + x = 180°
x = 15°
The angle measure will be 15°.
Answer: (x-8)(x+6)
Step-by-step explanation: For this equation, you need to figure out what two numbers add up to add -2, and multiply to get -48.
These numbers are +6 and -8. So the factored pair will be (x+6)(x-8)
Hope this helps:)