Answer:
see explanation
Step-by-step explanation:
1
Given
2x² - 16 = 0 ( add 16 to both sides )
2x² = 16 ( divide both sides by 2 )
x² = 8 ( take the square root of both sides )
x = ±
= ± 2
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2
Given
- 5x² + 9 = 0 ( subtract 9 from both sides )
- 5x² = - 9 ( divide both sides by - 5 )
x² =
( take the square root of both sides )
x = ±
= ± 
-----------------------------------------
3
Given
6x² - 15 = 27 ( add 15 to both sides )
6x² = 42 ( divide both sides by 6 )
x² = 7 ( take the square root of both sides )
x = ± 
X=180 and for some reason I need 20 characters so blah
Answer:
There is no picture or graph to go with the question so I am afraid I will not be able to give you a specific answer.
To find out if a point (x, y) is on the graph of a line, we plug in the values into that equation and see if we get a true statement, such as 10 = 10. If we get something different, like 6 = 4, we know that the point is not on the line because it does not satisfy the equation. Plug in (-301, 601) into the equation of the line to see whether that point lies on it or not.
Step-by-step explanation:
Suppose the equation of the straight line that passes through E and F is this:
y = 7x + 2
We are to figure out whether or not the point (1, 10) lies on that line. In order to do this we would plug in (1, 10) into the equation, with 1 being x and 10 being y.
10 = 7(1) + 2 = 7 + 2 = 9
10 = 9 is a false statement. Therefore, the point (1, 10) does NOT lie on the line y = 7x + 2.
If you were to provide an image or graph that shows the equation of line AB then perhaps I would be able to answer your question with a specific answer.
Here you go, hope this helps!