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avanturin [10]
3 years ago
10

What is 16,107,320 written in word form

Mathematics
1 answer:
Colt1911 [192]3 years ago
8 0
Sixteen million one hundred seven thousand three hundred and twenty
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Solve the quadratic equation by taking square roots.
Stolb23 [73]

Answer:

see explanation

Step-by-step explanation:

1

Given

2x² - 16 = 0 ( add 16 to both sides )

2x² = 16 ( divide both sides by 2 )

x² = 8 ( take the square root of both sides )

x = ± \sqrt{8} = ± 2\sqrt{2}

------------------------------------

2

Given

- 5x² + 9 = 0 ( subtract 9 from both sides )

- 5x² = - 9 ( divide both sides by - 5 )

x² = \frac{9}{5} ( take the square root of both sides )

x = ± \sqrt{\frac{9}{5} } = ± \frac{3}{\sqrt{5} }

-----------------------------------------

3

Given

6x² - 15 = 27 ( add 15 to both sides )

6x² = 42 ( divide both sides by 6 )

x² = 7 ( take the square root of both sides )

x = ± \sqrt{7}

4 0
4 years ago
Solve for n please, with work , thank you!
Paul [167]

\huge \boxed{\mathfrak{Question} \downarrow}

\sf1 - 3 n \gt - 1 - 4 ( 2 n - 8 )

  • Solve the inequality algebraically.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\sf1 - 3 n \gt - 1 - 4 ( 2 n - 8 )

  • Use the distributive property to multiply -4 by 2n-8.

\sf1-3n>-1-8n+32

  • Add -1 and 32 to get 31.

\sf1-3n>31-8n

  • Add 8n to both sides.

\sf1-3n+8n>31

  • Combine -3n and 8n to get 5n.

\sf1+5n>31

  • Subtract 1 from both sides.

\sf5n>31-1

  • Subtract 1 from 31 to get 30.

\sf5n>30

  • Divide both sides by 5. As 5 > 0, the direction of the inequality remains the same.

\sf \: n>\frac{30}{5}  \\

  • Divide 30 by 5 to get 6.

\boxed{ \boxed{ \bf \: n>6 }}

3 0
3 years ago
Read 2 more answers
Help!!!!!please!!!!!
san4es73 [151]
X=180 and for some reason I need 20 characters so blah
6 0
3 years ago
C is the point (-301, 601)<br> Does C lie on the straight line passing through A and B?
Marat540 [252]

Answer:

There is no picture or graph to go with the question so I am afraid I will not be able to give you a specific answer.

To find out if a point (x, y) is on the graph of a line, we plug in the values into that equation and see if we get a true statement, such as 10 = 10. If we get something different, like 6 = 4, we know that the point is not on the line because it does not satisfy the equation. Plug in (-301, 601) into the equation of the line to see whether that point lies on it or not.

Step-by-step explanation:

Suppose the equation of the straight line that passes through E and F is this:

y = 7x + 2

We are to figure out whether or not the point (1, 10) lies on that line. In order to do this we would plug in (1, 10) into the equation, with 1 being x and 10 being y.

10 = 7(1) + 2 = 7 + 2 = 9

10 = 9 is a false statement. Therefore, the point (1, 10) does NOT lie on the line y = 7x + 2.

If you were to provide an image or graph that shows the equation of line AB then perhaps I would be able to answer your question with a specific answer.

8 0
2 years ago
Triangle ABC is an isosceles triangle. Sides AB and BC are congruent.
Advocard [28]
Here you go, hope this helps!

8 0
4 years ago
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