<span>The triangle on paper is 5 inches wide by 7 inches high.</span><span>
</span><span>
If 1 inch on paper is equal to 1.5 feet on paper, then you need to multiply all dimensions by 18 because 1.5 feet is equal to 18 inches and you are getting 18 inches on the real banner for every inch on the paper banner. </span><span>
5 * 18 = 90 inches from the base of the rear triangle.</span><span>
7 * 18 = 125 inches for the height of the rear triangle. </span><span>
</span><span>The area of the paper triangle will be 5 * 7 / 2 = 35/2 square inches.</span><span>
The area of the rear triangle will be 90 * 125 / 2 = 5625 square inches. </span><span>
regarding feet:
The base of the real banner will be 125/12 = 10.41666666....... feet.</span><span>
the height of the real banner will be 90 / 12 = 7.5 feet.</span><span>
the area of the real banner will be 5625 / 12^1 = 5625 / 144 = 39.0625 square feet.</span><span>
</span>
Answer: For y it's y=4x−12 and for x it's x=12+y/4
Step-by-step explanation:
SOLVING FOR X
8x-2y=24
2(4x−y)=24
4x−y=24/2
4x−y=12
4x=12+y
x=12+y/4
SOLVING FOR Y
8x-2y=24
2(4x−y)=24
4x−y=24/2
4x−y=12
−y=12−4x
y=−12+4x
y=4x−12
Hope this helps, have a BLESSED AND WONDERFUL DAY! As well as a great Black History Month and Valentine's day! :-)
- Cutiepatutie ☺❀❤
The train traveled 60 miles per hour since 360 miles divided by 6 hours gives you 60 mph
Answer:
921
Step-by-step explanation:
If he recives 3x amount than his oppenent
than we would divided by 3 from his score to find oppponets score
so....
2763 divided by 3=921
Answer: 
Step-by-step explanation:
In order to solve this exercise it is important to remember the multiplication of signs. Notice that:

In this case you have the following expression given in the exercise:

Where the variable is "j".
When you multiply signs, you get:

Now you need to identify that like terms and then you need to add them (or combine them). So, applying this procedure you get that the simplified form of the expression is the shown below:

As you can observe, you get a 2nd degree binomial.