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Sliva [168]
4 years ago
6

Date

Mathematics
1 answer:
Karo-lina-s [1.5K]4 years ago
7 0

Answer:

so what

Step-by-step explanation:

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. A group of ten candy bars has an average cost of $0.89 per candy bar. How many bars must be bought at the cost of $0.72 a piec
Cloud [144]

we will have to buy 12.

<h3>How to solve?</h3>

We know to begin with that for x candy bards:

x / 10 = 0.89; x = 8.90

We are trying to ascertain how many bars (y) must be added to this to amount to have an average of 0.80.  This is represented:

(8.9 + 0.72y) / (10 + y) = 0.8

8.9 + 0.72y = 0.8 (10 + y)

8.9 + 0.72y = 8 + 0.8y

8.9 – 8 = 0.8y - 0.72y

0.9 = 0.08y

y = 0.9 / 0.08 = 11.25

However, since we cannot have a partial amount of candy bars, we will have to buy 12.

Learn more

brainly.com/question/4313883

#SPJ4

5 0
2 years ago
A police car drives 144 km in 240 minutes. what is its average speed in kilometers per hour?
NeTakaya
Answer: 36km/hour

Explanation: 144/4
7 0
2 years ago
Paco's cell phone carrier charges him $0.20 for each text message he sends or receives, $0.15 per minute for calls, and a $15 mo
Katarina [22]

Given:

Paco's cell phone carrier charges him $0.20 for each text message he sends or receives, $0.15 per minute for calls, and a $15 monthly service fee. Paco is trying to keep his bill for the month below $30.

To Find:

The number of texts 't' Paco can send/receive in a month.

Answer:

0\leq t

best describes the number of texts he can send or receive to keep his bill less than $30 in a month.

Step-by-step explanation:

Paco wants to keep is monthly bill below $30.

We see that he has to pay a foxed monthly service fee of $15. This means he is only left with a limit of $30 - $15 = $15 for his monthly calls and texts.

That is, the amount he has to pay for texting and calling has to be less than $15.

For texts, the cell phone carrier charges $0.20 for sending/receiving texts.

For calls, he is charged $0.15 per minute.

Let the number of text messages Paco can send or receive in a month be denoted by 't'.

Let the number of minutes Paco can call in a month be denoted by 'c'.

Then, the total cost of text messages he can send or receive per month would be 0.20t and the total cost of the minutes he spends on calls would be 0.15c. Together, the sum of these has to be less than $15 if his monthly bill has to be kept less than $30 (accounting for the monthly service fee).

So,

0.20t+0.15c

The number of texts he can send will dpend on the number of minutes he spends on his calls. For Paco to spend maximum number of texts, he has to spend 0 minutes on calls.

So, putting c = 0, the aboce equation can be written as

0.20t+0

That is, Paco has to send and receive less than 75 texts.

So,

0\leq t

best describes the number of texts he can send or receive to keep his bill less than $30 in a month.

3 0
3 years ago
Read 2 more answers
Pentagon ABCDE is dilated according to the rule
Tema [17]
The coordinates of A in the pre-image is (-1,2).

D0, 3(x,y) means (x,y) → (3x,3y)

A'(-3,6)
B'(-0.5, 8)
C'(2,6)
D'(1,3)
E'(-2,3)

The coordinates of the pre-image are multiplied by 3 resulting to the coordinates of the given image. So, we simply divide each value of x and y by 3 to get the coordinates of the pre-image.

A'(-3,6) → -3/3 = -1 ; 6/3 = 2 → A(-1,2)

6 0
3 years ago
Read 2 more answers
CORRECT AND CLEAR ANSWER WILL BE GIVEN BRAINLIEST An object of mass 0.30 kg is thrown vertically upwards and reaches a height of
Natalka [10]

Answer:

Final potential energy = 24 Joule

The velocity with which object must be thrown = 4 \sqrt{10} m/s

Step-by-step explanation:

<u>Given:</u>

Mass of object, m = 0.30 Kg

Height of object, h = 8 m

Acceleration due to gravity, g = 10 ms^{-2}

a) Formula for Potential Energy:

E_p =mgh

Where m is the mass of object

g is acceleration due to gravity and

h is the height of object

Putting the values of m, g and h

E_p = 0.3 \times 10 \times 8\\\Rightarrow E_p =24 J

b) Formula for initial and final velocity:

v^{2}   =u^{2} +2gh

where v is the final velocity

u is the initial velocity with which the object is thrown

g is acceleration due to gravity and

h is the height obtained by object

here v = 0 at the height 8 m because it will come to rest at the point it attains the maximum height.

h = 8m

g = -10 ms^{-2} (negative because the object's velocity is decreasing)

Putting the values to find 'u':

0^{2}   =u^{2} +2 \times -10 \times 8\\\Rightarrow u^{2} = 160\\\Rightarrow u = 4 \sqrt{10}\ m/s

7 0
3 years ago
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