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UkoKoshka [18]
3 years ago
9

Please please help me out

Mathematics
1 answer:
mr Goodwill [35]3 years ago
5 0

Answer:

12

Step-by-step explanation:

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Felipe is a software salesman. His base salary is $2500, and he makes an additional S90 for every copy of Math is Fun he sells
BartSMP [9]
Answer:
1035 feet
Step-by-step explanation:
Given:
OB = 900 m
«BOH = 49°
Find BH:
BH/BO =tan 49
BH = BO tan 49
BH = 900 * 1.15
BH = 1035
3 0
2 years ago
34/23 as a decimal rounded to the nearest tenth
Ainat [17]

Answer:

1.5

Step-by-step explanation:

1.47826086

rounded to the nearest tenth is 1.5

4 0
2 years ago
CAN SOMEONE PLEASE HELP ME I'M STUCK. PLEASE<br> I don't understand and know how to solve it.
xenn [34]

Answer:

7/10

Step-by-step explanation:

red + green = 50 + 20 = 70 marbles

Total marbles = 50 + 30 + 20 = 100 marbles

P(red or green) = 70/100

P(red or green) = 7/10

8 0
2 years ago
The line inside this circle is its
Alex777 [14]
The answer will be (D)
Hope this helps
May i plz have brainliest?
6 0
2 years ago
A bag contains 4 white,5 blacks and 2 blue balls. 3 balls are drawn one after the other without replacement from the bag .what i
Doss [256]

Answer:

24/99

Step-by-step explanation:

From the question given above, the following data were obtained:

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

Probability that they are of different color =?

Next, we shall determine the total number of balls in the bag. This can be obtained as follow:

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

TOTAL = 4 + 5 + 2 = 11 balls

Next, we shall determine the possible outcome of draw. This can be obtained as follow.

The possible outcome could be:

WBLB or WBBL or BBLW or BWBL or BLBW or BLWB

Next we shall determine the probability of each of outcomes.

Since the ball is drawn without replacement, it means the total number of ball will reduce after each draw.

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

TOTAL = 11

P(WBLB) = 4/11 × 2/10 × 5/9 = 40/990

P(WBLB) = 4/99

P(WBBL) = 4/11 × 5/10 × 2/9 = 40/990

P(WBBL) = 4/99

P(BBLW) = 5/11 × 2/10 × 4/9 = 40/990

P(BBLW) = 4/99

P(BWBL) = 5/11 × 4/10 × 2/9 = 40/990

P(BWBL) = 4/99

P(BLBW) = 2/11 × 5/10 × 4/9 = 40/990

P(BLBW) = 4/99

P(BLWB) = 2/11 × 4/10 × 5/9 = 40/990

P(BLWB) = 4/99

Finally, we shall determine the probability that they are of different color. This can be obtained as follow:

P(WBLB) = 4/99

P(WBBL) = 4/99

P(BBLW) = 4/99

P(BWBL) = 4/99

P(BLBW) = 4/99

P(BLWB) = 4/99

Probability that they are of different color =?

Probability that they are of different color = P(WBLB) + P(WBBL) + P(BBLW) + P(BWBL) + P(BLBW) + P(BLWB)

= 4/99 + 4/99 + 4/99 + 4/99 + 4/99 + 4/99

= (4 + 4 + 4 + 4 + 4 + 4)/99

= 24/99

Thus, the probability that they are of different color is 24/99

4 0
3 years ago
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