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3 years ago

6

What are the zeros of the polynomial function

1 answer:

Rasek [7]3 years ago

3 0

Answer:

The zeros are 0, -2, and 4.

Step-by-step explanation:

Factor equation into x(x+2)(x-4)=0

Solve.

x+2=0

x=-2

x-4=0

x=4

and do not forget the x in the front, which needs no solving, as it equals zero.

x=0

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196 pages fewer than savannah

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The graph below shows the height of a kicked soccer ball f(x), in feet, depending on the distance from the kicker x, in feet: Pa

Advocard [28]

the complete question in the attached figure

part A

the x intercept 0 is the point where the ball was hit, the x intercept 20 is the point where the ball fell back to the ground, 20 feet away from the kicker.

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3 years ago

Please help me if you can

MA_775_DIABLO [31]

Answer:

y = .025x +20

The y intercept is the value when x = o, or the starting value. In this case, it is the temperature in degrees F at a depth of 0 meters.

Step-by-step explanation:

We have a point a (0,20) and a point at (2 , 20.05)

We can find the slope from

m = (y2-y1)/(x2-x1)

= (20.05-20)/(2-0)

= .05/2

=.025

One of the points (0,20) is the y intercept since x=0

We can use the slope intercept form of the equation

y= mx+b

y = .025x +20

The y intercept is the value when x = o, or the starting value. In this case, it is the temperature in degrees F at a depth of 0 meters.

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3 years ago

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jekas [21]

Answer:

-8/5, 13/5

Step-by-step explanation:

Use the process of elimination to find out the y and plug the y in to get the x.

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Complete the table of values for this absolute value function. Then use the drawing tool(s) to graph the function. F(x)-2|x+1|-1

rusak2 [61]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the equation

$f\left(x\right)=-2|x+1|-1$

As some of the absolute rules are:

$\left|a\right|=a,\:a\ge 0$

$\:|-a|=a,\:\quad \:a>0$

NOW, let us solve!

Let us substitute all the table values

Putting x = -4

$y=-2\left|-4+1\right|-1$ ∵ $\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$y=-6-1$

$y=-7$

So, when x = -4, then y = -7

Putting x = -3

$y=-2|-3+1|-1\:$

$y=-4-1$

$y=-5$

when x = -3, then y = -5

Putting x = -2

$y=-2\left|-2+1\right|-1$

$y=-2-1$

$y=-3$

when x = -2, then y = -3

Putting x = -1

$y=-2\left|-1+1\right|-1$

$y=-0-1$

$y=-1$

when x = -1, then y = -1

Putting x = 0

$y=-2\left|0+1\right|-1$

$y=-2-1$

$y=-3$

when x = 0, then y = -3

Putting x = 1

$y=-2\left|1+1\right|-1$

$y=-4-1$

$y=-5$

when x = 1, then y = -5

The graph is also attached below.

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3 years ago