1/4 remained
2/4 - mist + 1/4 -flout = 3/4
4/4 - 3/4 = 1/4
Step-by-step explanation:
When x = -2, x + 2 = (-2) + 2 = 0.
Answer:
yes
Step-by-step explanation:
well plug it in: y=6x -> y=6(3/9) and solve, yes if theres a slope of 1
By definition, the volume of the cone is given by:
V = (1/3) (π) (r ^ 2) (h)
Substituting values we have:
V = (1/3) (π) ((4/2) ^ 2) (5)
V = (20/3) (π)
Then, the volume of the cylinder is:
Vc = 3 * V
Vc = 3 * (20/3) (π)
Vc = 20π
Answer:
the volume of the original cylinder jesse bought is:
Vc = 20π
Check the picture below.
so we know the radius of the semicircle is 2 and the rectangle below it is really a 4x4 square, so let's just get their separate areas and add them up.
![\stackrel{\textit{area of the semicircle}}{\cfrac{1}{2}\pi r^2}\implies \cfrac{1}{2}(\stackrel{\pi }{3.14})(2)^2\implies 3.14\cdot 2\implies 6.28 \\\\\\ \stackrel{\textit{area of the square}}{(4)(4)}\implies 16 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{sum of both areas}}{16+6.28=22.28}~\hfill](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20semicircle%7D%7D%7B%5Ccfrac%7B1%7D%7B2%7D%5Cpi%20r%5E2%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B2%7D%28%5Cstackrel%7B%5Cpi%20%7D%7B3.14%7D%29%282%29%5E2%5Cimplies%203.14%5Ccdot%202%5Cimplies%206.28%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20square%7D%7D%7B%284%29%284%29%7D%5Cimplies%2016%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bsum%20of%20both%20areas%7D%7D%7B16%2B6.28%3D22.28%7D~%5Chfill)