All cone-shaped cups have the same height in 8 inches. They just differ in their diameters. To solve for the volume of the regular and jumbo sizes, let's use the formula for the volume of cone
V = (1/3)*pi*(r^2)*h
r is just the half of the diameter, h is the height which is equal to 8
Regular size:
V = (1/3)*pi*((4/2)^2)*8
V = 33.5 cube inches
Jumbo size:
V = (1/3)*pi*((8/2)^2)*8
V = 134.0 cube inches
Answer:
8.25475 m
Step-by-step explanation:
pi*r^3 is the formula for a sphere.
Using this, pi is a nmber (about 3.14) and we only don't know the radius, but we know what it equals.
pi*r^3=1,767.1
First divide by pi, then get ride of the cube by cube rooting both sides.
The cube root of 1767.1/pi (remember to cube root both denominator and numberator!!!) is about 8.25475 m
Answer:
The shadow is decreasing at the rate of 3.55 inch/min
Step-by-step explanation:
The height of the building = 60ft
The shadow of the building on the level ground is 25ft long
Ѳ is increasing at the rate of 0.24°/min
Using SOHCAHTOA,
Tan Ѳ = opposite/ adjacent
= height of the building / length of the shadow
Tan Ѳ = h/x
X= h/tan Ѳ
Recall that tan Ѳ = sin Ѳ/cos Ѳ
X= h/x (sin Ѳ/cos Ѳ)
Differentiate with respect to t
dx/dt = (-h/sin²Ѳ)dѲ/dt
When x= 25ft
tanѲ = h/x
= 60/25
Ѳ= tan^-1(60/25)
= 67.38°
dѲ/dt= 0.24°/min
Convert the height in ft to inches
1 ft = 12 inches
Therefore, 60ft = 60*12
= 720 inches
Convert degree/min to radian/min
1°= 0.0175radian
Therefore, 0.24° = 0.24 * 0.0175
= 0.0042 radian/min
Recall that
dx/dt = (-h/sin²Ѳ)dѲ/dt
= (-720/sin²(67.38))*0.0042
= (-720/0.8521)*0.0042
-3.55 inch/min
Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min
1: slope = 2/1 or 2
2: slope = 5/-5
3: slope = 3/2
4: slope = 7/-4
5: slope = 3/5
6: slope = 2/-8
7: slope = 6/2 or 3
8: slope = 2/-4
9: slope = 1/6
I think it would be A because if you multiply the square by a 30 thinking there all the same space between it will give u 120 square yards