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4 years ago

Answer the Question below (45 points)

Mathematics

1 answer:

iren [92.7K]4 years ago

8 0

3x-5=-6x+13 : Given

3x=-6x+18 : Addition property of Equality

9x=18: Subtraction property of Equality

x=2: Division Property of Equality

Step-by-step explanation:

We need to give justification to each step

Step 1:

3x-5=-6x+13

This is the question given, which we need to solve and find value of x.

Justification: Given

Step 2:

Adding 5 on both sides of the equation using addition property of equality.

3x-5+5=-6x+13+5

Simplifying

3x=-6x+18

Justification: Addition property of Equality

Step 3:

Adding 6x on both sides of the equation

3x+6x=-6x+18+6x

9x=18

Justification: Subtraction property of Equality

Step 4:

Divide both sides of the equation by 9, to find the value of x using division property of equality

9x/9=18/9

x=2

Justification: Division Property of Equality

Keywords: Solving Equations

Learn more about Solving Equations at:

#learnwithBrainly

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There are 12 men and 24 women in a chorus. What percent of the entire chorus is composed of women?

kati45 [8]

About 66 percent.
Because 24/36 are women, keep simplifying that divide by 6, 4/6, divide by 2, 2/3 = 0.66 = 66%.

7 0

4 years ago

the population of a town increases at a rate proportional to its population with an initial population of 1000. The corect initi

anyanavicka [17]

Answer:

This means that the correct initial value problem for the population p(t) as a function of time is is $P(0) = 1000$

Step-by-step explanation:

The population of a town increases at a rate proportional to its population:

This means that this situation is modeled by the following differential equation:

$\frac{dP}{dt} = kP$

In which k is the growth rate.

By separation of variables, the solution is given by:

$P(t) = P(0)e^{kt}$

In which P(0) is the initial population.

Initial population of 1000.

This means that the correct initial value problem for the population p(t) as a function of time is is $P(0) = 1000$

5 0

3 years ago

Geometry help needed!

lilavasa [31]

Answer:

13.76

Step-by-step explanation:

Area of the whole

The area of the whole = s^2 (the firgure is a square

s = 8

Area of the whole = 8^2 = 64

Area of the unshaded part

The 2 half circles = 1 whole circle

The radius of the 1/2 circle = 4 (eight has been cut in half)

Area of two half circles = 2* (pi r^2/2)

Area of two half circles = 2 * (pi 4^2/2)

area of two half circles = 16*pi

Area of the shaded area

Area of the shaded area = area of the whole - area of the unshaded area

Area of the shaded area = 64 - 16*pi

Area of the shaded area = 64 - 3.14*16 = 13.76

4 0

3 years ago

DOG A dog is leashed to the corner of a house. How much running area does the dog have? Explain how you found your answer.

Eduardwww [97]

Answer:

The area will be $\frac{3\pi r^{2} }{4}$ where r is the length of the leash.

Step-by-step explanation:

The area of a circle is pi times the radius squared. One forth of that area is not available for the dog to run: its the corner of the house. so what's left is 3/4 of the area of the circle. (3/4)πr²

Since the length of the leash is not given in the question, no specific Area can be answered. Once that value is substituted for r, the actual area can be calculated.

7 0

3 years ago

Please answer ASAP. A baseball is hit upward from a platform that is m high at an initial speed of 29m/s. The approximate height

kotegsom [21]

Answer:

a) about 0.7 seconds to 5.1 seconds.

b) Listed below.

Step-by-step explanation:

h - 1 = -5x^2 + 29x

h = -5x^2 + 29x + 1

a) We will find the amount of time it takes to get to 18 meters.

18 = -5x^2 + 29x + 1

-5x^2 + 29x + 1 = 18

-5x^2 + 29x - 17 = 0

We will then use the quadratic formula to find the answer.

[please ignore the A-hat; that is a bug]

$\frac{-29±\sqrt{29^2 - 4 * -5 * -17} }{2 * -5}$

= $\frac{-29±\sqrt{841 - 340} }{-10}$

= $\frac{-29±\sqrt{501} }{-10}$

= $\frac{-29 ± 22.38302929}{-10}$

= $\frac{-6.616970714}{-10}$ and $\frac{-51.38302929}{-10}$

= 0.6616970714 and 5.138302929

So, the time period for which the baseball is higher than 18 metres ranges from about 0.7 seconds to 5.1 seconds.

b) Restrictions on the domain and range of the function are that the domain and range can never be negative, since time cannot be negative, and height cannot be negative. The height cannot exceed the vertex of the parabola, since that is the highest the ball will ever go. It cannot exceed that height since gravity will cause the ball to fall down.

Hope this helps!

5 0

3 years ago