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3 years ago

13

The formula for the area of a triangle is A= 1/2 bh, where b is the base of the triangle and h is the height of the triangle. Wh

at is the length of the base if the area is 32 cm^2 and the height is 4cm

1 answer:

Yanka [14]3 years ago

6 0

Answer:

16

Step-by-step explanation:

32=1/2(4)b

32=2b

16=b

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Anvisha [2.4K]

Answer:

B

Step-by-step explanation:

(x,y) = P + (a)t

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HELP PLEASE <br> solve the right triangle

aleksandrvk [35]

Answer:

Part 1) $FG=4.4\ units$

Part 2) $EF=3.9\ units$

Part 3) $m\angle G=63^o$

Step-by-step explanation:

step 1

Find the measure of length side FG

In the right triangle EFG

we know that

$sin(27^o)=\frac{GE}{FG}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(27^o)=\frac{2}{FG}$

$FG=\frac{2}{sin(27^o)}=4.4\ units$

step 2

Find the measure of length side EF

In the right triangle EFG

we know that

$cos(27^o)=\frac{EF}{FG}$ ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

$cos(27^o)=\frac{EF}{4.4}$

$EF=cos(27^o)(4.4)=3.9\ units$

step 3

Find the measure of angle G

we know that

$m\angle G+27^o=90^o$ ---> by complementary angles in a right triangle

$m\angle G=90^o-27^o=63^o$

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Answer:

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Step-by-step explanation:

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