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3 years ago

Sarabi drove 20 mi at 40 mph. How long did she drive?

1 answer:

8 0

1/2 of the time

d=st
distance=speed times time
we want to find time
divide both sides by speed
d/s=t

d=20
s=40
20/40=t
1/2=t
this is in hours

she drove for 1/2 hour or 30 mins

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DO NOT ANSWER WITH BITLY LINKS! Find the measure of the arc or central angle indicated. Assume that lines that appear to be diam

Svetach [21]

Answer:

135°

Step-by-step explanation:

LI = LM+MI = 35+80

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3 years ago

Sweetums finds that the cost of making a certain candy bar .15 per bar and that the fixed rate is 600 per week if each bar sells

PilotLPTM [1.2K]

We know that:

Profit = Revenue - Cost

Let us say x number of candies are made per week.

Finding Cost per week:

Cost of making 1 bar = 0.15

Cost of making x bars = 0.15x

Fixed rate of making candies per week = 600

Total cost of making x candies per week = 600 + 0.15x

Now let us find Revenue:

Selling price of each bar = 1.50

Selling price of x bars = 1.50x

Now we have to find profit,

Profit = Revenue - Cost

In order to have profit Revenue - Cost >0

So plugging values of revenue and cost to get number of candies,

$1.50x-(0.15x+600)>0$

$1.50x-0.15x-600>0$

$1.35x-600>0$

$1.35x>600$

x>444.44

Rounding off

x>444

Answer: The company must sell greater than 444 candies in order to make profit.

7 0

3 years ago

The scale factor of the dimensions of two similar wood floors is 5 : 3. It costs $144 to refinish the smaller wood floor. At t

Eva8 [605]

Answer: 240

Step-by-step explanation:

144/3 = 48

5x48= 240

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3 years ago

Danielle sells beauty supplies and earns a base salary of $450 per week plus a 9% commission on sales. During one particular wee

Anna007 [38]

Answer:

Should be 530.55 total that week

And 80.55 in commissions

7 0

3 years ago

Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop

xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

f(x)=log (3 x) +5 x²

$f'(x)=\frac{1}{3x}+10 x$

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248$

$x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012$

$x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057$

$x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052$

So, root of the equation =0.205 (Approx)

Approximate relative error

$=\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41$

Approximate relative error in terms of Percentage

=0.41 × 100

= 41 %

7 0

3 years ago