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Neporo4naja [7]
2 years ago
7

Please help 4 math pages with questions. 1 has all the circle graphs, and all the other 3 have each circle graphs question. Plea

se help.

Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
8 0

Answer:

Favorite chip Answers v

Step-by-step explanation:

1. How many were surveyed? 82+8+18+62=100

2. How many said Jalepeno was their favorite? 8/100 0r 2/25 or 8%

3. How many said BBQ was their favorite?62/100 or 31/50 or 62%

4. How would it effect your final answer if the percentages did not add up to 100%? This means that your percentages are wrong. In a circle graph the percentages always equal 100%!

5. Is it possible to determine a missing percentage in a circle graph? Yes, we can always assume the total percentage is 100 so you add your given percentages together and then subtract that total from 100 to find the missing percentage.

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A store is having a sale on used video game. Each game cost $12. Write an algebraic expression to represent the cost of buying v
alexandr1967 [171]
The algebraic expression you would write is 12v
8 0
3 years ago
Ben and Tom each take a driving test.
GaryK [48]

Answer:

(b)0.56

(c)0.38

Step-by-step explanation:

(a)The tree diagram is attached.

P(Ben Fails)=1-0.8=0.2

P(Tom Fails)=1-0.7=0.3

(b)Probability that  both will pass their driving test.

P(both will pass)=0.8 X 0.7 =0.56

(c)Probability that  only one of them will pass their  driving test.

P(Tom Bass, Ben Fails OR Ben Pass, Tom Fails)

=(0.7 X 0.2)+(0.8 X 0.3)

=0.14+0.24

=0.38

3 0
3 years ago
What is the equation<br> example:: y=3/1x-6
hichkok12 [17]

Answer:

y = 4/6x - 4

Step-by-step explanation:

y = mx + b, m = slope and b = y intercept

Rise over run

Rise = +4

Run = +6

This means the slope is 4/6.

The y intercept is at -4.

Now, plug in the numbers for y = mx + b

y = 4/6x - 4

4 0
3 years ago
What is the solution to this equation? 2x+4=16
AlekseyPX

2x+4=16\\\\2x=12\\\\x=6

3 0
3 years ago
Solve the following equation. X cubed minus 6X squared plus 6X equals zero
anyanavicka [17]

We have to solve this equation:

x^3-6x^2+6x=0

Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:

\begin{gathered} x^3-6x^2+6x=0 \\ x(x^2-6x+6)=0 \end{gathered}

Now we can find the roots of the quadratic polynomial as:

\begin{gathered} x=\frac{-(-6)\pm\sqrt[]{(-6)^2-4\cdot1\cdot6}}{2\cdot1} \\ x=\frac{6\pm\sqrt[]{36-24}}{2} \\ x=\frac{6\pm\sqrt[]{12}}{2} \\ x=\frac{6\pm\sqrt[]{4\cdot3}}{2} \\ x=\frac{6\pm2\sqrt[]{3}}{2} \\ x=3\pm\sqrt[]{3} \\ x_1=3-\sqrt[]{3} \\ x_2=3+\sqrt[]{3} \end{gathered}

Then, the solutions to the equation are:

x = 0

x = 3 - √3

x = 3 + √3

4 0
1 year ago
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