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olga_2 [115]
2 years ago
8

How can these terms be combined: -2x + 11 + 6x - 5 *

Mathematics
1 answer:
DaniilM [7]2 years ago
5 0
Hey :)

The answer is 4x + 6

−2x + 11+ 6x −5
Combine −2x and 6x to get 4x


4x + 11 −5
Subtract 5 from 11 to get 6

= 4x + 6

Hope this helps :)
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Determine the maximum number of zeros and the x-intercepts of the function: (x^2-x-2)(3x-2)
schepotkina [342]

Answer:

3

Step-by-step explanation:

note that zeros and x-intercepts are the same with different names

There are 2 zeros from the quadratic factor and 1 from the linear factor.

To find them equate the function to zero, that is

(x² - x - 2)(3x - 2) = 0

(x - 2)(x + 1)(3x-2) = 0 ← factoring the quadratic

equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

x + 1 = 0 ⇒ x = - 1

3x - 2 = 0 ⇒ x = \frac{2}{3}


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2 years ago
Suzanne bakes 350 cookies in 5 hours, and cole bakes 400 cookies in 8 hours Part A: what are the unit rates at which suzanne and
mrs_skeptik [129]

Answer:

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3 years ago
What is the area of the quartz crystal he was studying, in square feet. <br><br><br> Help please
Nataly_w [17]
105 is the answer to this question
6 0
3 years ago
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P(t) = 250 * (3.04)^t/1.98,
Alex17521 [72]

Answer:

The concept which best describes the change of the population is the derivative of p(t)=250(3.04)^{\frac{t}{1.98}}.

Step-by-step explanation:

Observe that the function p(t)=250(3.04)^{\frac{t}{1.98}} describes the amount of rabbits at the time t (in years) but  no the rate of change of the population at a given instant. So you have to use the derivative of p(t) to obtain that rate of change at any instant. For example, if we derivate the function p(t)=250(3.04)^{\frac{t}{1.98}} we obtain:

p'(t)=250\cdot \log(\frac{1}{1.98})(3.04)^{\frac{t}{1.98}}

And if we want to find the rate of change at t=5 years we evaluate

p'(5)=250\cdot \log(\frac{1}{1.98})(3.04)^{\frac{5}{1.98}}=2326 rabbits/year

5 0
3 years ago
Drag and drop a statement or reason to each box to complete the proof.
yaroslaw [1]

hope this helps :)

your question helped me and so ill help you

5 0
3 years ago
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