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LUCKY_DIMON [66]
3 years ago
8

In the xy-plane, the midpoint M of segment AB has coordinates (-1,3), and point A has coordinates

Mathematics
1 answer:
Marina CMI [18]3 years ago
7 0
I think it’s 3 because if u do a -3 and a positive 0 the answer would be 3
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Is 9 a possible solution for -2x + 4 ≥ -14?
konstantin123 [22]

Answer:

Yes

Step-by-step explanation:

-2(9)+4= -14  and -14 is equal to -14.

6 0
3 years ago
The senior classes at High School A and High School B planned separate trips to the county fair. The senior class at High School
elena-s [515]

vans = v, buses = b, students = s

8v + 8b =312s ...eqn 1

9v + 4b = 196s ...eqn 2

divide eqn 1 by 2

4v + 4b = 156s ...eqn 3

eqn 2 - eqn 3

5v = 40s

v = 8s

subst v = 8s in eqn 2

72s + 4b = 196 s

b = 31s

answer

each van holds 8 students and each bus holds 31 students

8 0
3 years ago
Additive inverse of -2/5​
Inessa [10]

Hello! The additive inverse of -2/5 is 2/5.

if you add -2/5+2/5, you will get 0, so these two numbers are opposites and additive inverses.

Hope this helps you!

~Just a joyful teen

SilentNature\\(GraceRosalia)

4 0
3 years ago
dad planted a four year old maple tree in the front yard the apple tree in the backyard is 5 times as old as the maple tree the
RUDIKE [14]

the apple tree is 20 and the oak tree is 40

hopes this helps,

Xeno

4 0
4 years ago
Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, 32% of all homeowners are ins
Bumek [7]

Answer:

P(X = 0) = 0.2138

P(X = 1) = 0.4025

P(X = 2) = 0.2841

P(X = 3) = 0.0891

P(X = 4) = 0.0105

Step-by-step explanation:

For each homeowner, there are only two possible outcomes. Either they have invested in earthquake insurance, or they have not. The probability of a home owner having invested in earthquake insurance is independent from other homeowners. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

32% of all homeowners are insured against earthquake damage.

This means that p = 0.32

Four homeowners are to be selected at random.

This means that n = 4

Find the probability distribution of X.

This is the probability of each outcome

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.32)^{0}.(0.68)^{4} = 0.2138

P(X = 1) = C_{4,1}.(0.32)^{1}.(0.68)^{3} = 0.4025

P(X = 2) = C_{4,2}.(0.32)^{2}.(0.68)^{2} = 0.2841

P(X = 3) = C_{4,3}.(0.32)^{3}.(0.68)^{1} = 0.0891

P(X = 4) = C_{4,4}.(0.32)^{4}.(0.68)^{0} = 0.0105

6 0
3 years ago
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