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vladimir2022 [97]
3 years ago
14

Write two sentences to compare 743.476 and 743.746

Mathematics
1 answer:
Vadim26 [7]3 years ago
5 0
743.476 < 743.746
743.746 > 743.476 
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A sample of 25 undergraduates reported the following dollar amounts of entertainment expenses last year:
Kaylis [27]

Answer:

A.

mean = 724.2

Median = 715

Mode = 768

B.

Range = 85

Standard deviation = 29.30

C.

Interval = [665.6, 782.8]

Step-by-step explanation:

Number of samples n = 25

Summation X= 769 + 691 + 699 +730+711+ 765+ 702 718 +719 +712+ 768 +688 +757+695 768 +735 +709 +758 +708+ 693 +736 700+ 687 +772 +715 = 18105

A.

1. Mean = 18105/25

= 724.2

2. Median is the middle value when arranged from the least value to the highest = 715

3. Mode is the number with the highest frequency = 768 (occured two times)

B.

1. Range = highest value - lowest value

Highest value = 772

Lowest value = 687

772-687 = 85

2. Standard deviation = √(X-barX)²/n-1

= √20604/25-1

=√858.5

= 29.30

Please check attachment for the full calculation of the standard deviation

C.

Interval

[Mean - 2(sd), mean + 2(sd)]

= [724.2-2x29.3, 724.2+2x29.3]

=[665.6, 782.8]

4 0
2 years ago
Which is the simplified expression for questions 1 2 3 4? (Look at photo)
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1. 9.5x + 1.5
2. 9x + 36
3. 4.8x + 2
4. 22x + 2
6 0
2 years ago
A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If
Blababa [14]

Answer: Our required probability is \dfrac{1}{2}

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = \dfrac{1}{3}

So, Probability of getting head from fair coin = \dfrac{1}{2}

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}

Hence, our required probability is \dfrac{1}{2}

No, the answer is not \dfrac{1}{3}

5 0
3 years ago
Jasper has an annual salary of $71,000, and his company pays him twice a month. What is the gross income per paycheck that Jaspe
Elan Coil [88]
Divide $71,000 by 24 because there are 12 months in a year and he gets paid 2 times a month. I got $2,958.33
5 0
3 years ago
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THIS QUESTION IS WORTH 33 POINTS!! PLEASE PLEASE HELP ME
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It's less than a whole number like 2/1 times 1/2 is 2/2 or 1
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3 years ago
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