Points equidistant from DE EF are in the bisector of angle DEF
points equidistant from EF DF are in the bisector of angle EFD
the sought after point is the intersection of bisectricess of triangle
Answer:
x=0
Step-by-step explanation:
substitute y=0
0= -x^2
then swap the sides
-x^2=0 ,
change the signs
x^2=0
set the base equal to 0
x=0
Answer:
F
Step-by-step explanation:
Multiply -3 by 6.5 and you'll get your answer :)
I hope I helped!
Answer:
10000000000
Step-by-step explanation:
10000000000
:) Hope this helps
