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2 years ago

7

In one year, 144 of the people enrolled in a college went on a winning outreach during the college year. It was 4/5 of the peopl

e enrolled in the college. How many of those enrolled in the college did not go on the outreach?
I know it's long, I'm sorry.
Thank you :)

1 answer:

Rudiy272 years ago

6 0

The school has 180 students 144 went 36 did not go to the outreach

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Pls answer fast my teacher is waiting!

a_sh-v [17]

Answer:

For company A, y = 24x + 42

For company B, y = 28x + 25

Step-by-step explanation:

x is the number of containers

y is the total cost

For company A, y = 24x + 42

For company B, y = 28x + 25

For the cost of both companies to be the same, then

24x + 42 = 28x + 25

28x - 24x = 42 - 25

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2 years ago

When y is 4, p is 0. 5, and m is 2, x is 2. If x varies directly with the product of p and m and inversely with y, which equatio

dmitriy555 [2]

Answer:

$\dfrac{xy}{pm}=8$

Step-by-step explanation:

If x varies directly as the product of p and m, and inversely with y, the relation can be written ...

x = k(pm)/y . . . . where k is the constant of proportionality

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This can be solved for k:

k = xy/pm

For the given values, the value of k is ...

k = (2)(4)/((0.5)(2)) = 8

Then the relation between the variables can be written ...

(xy)/(pm) = 8

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1 year ago

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

pychu [463]

Answer:

A=152

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Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

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Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

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Applying the following property of exponentials numbers in (II):

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Therefore $e^{-28k}$ can be written as $e^{-14k}.e^{-14k}$

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Replacing (I) in the previous equation:

$152=190-76e^{-14k}$

Solving for k:

Subtracting 190 both sides, dividing by -76:

$0.5=e^{-14k}$

Applying the base e logarithm both sides:

Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

$Ae^{-14(-Ln(0.5)/14)}=76\\Ae^{Ln(0.5)} =76\\A(0.5)=76$

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2 years ago

What are the values for matrix A?: 1 2 3 4 1 3 4 5 6 7 8 Noo 4 1 0 0 9 6 7 8 10 12 14 15 16 13 14 14 15 16

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2 years ago

Denise bought a box of 560 pieces of candy.4/5 of the pieces of the candy were fruity and 1/4 of the remaining pieces of candy w

Liula [17]

Answer:

<em>Number of Other flavor candy is 84.</em>

Step-by-step explanation:

Given that

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$\dfrac{4}{5} \times 560\\\Rightarrow 4 \times 112 =448$

Now, remaining pieces = Total pieces - Fruity pieces

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