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Lera25 [3.4K]
4 years ago
6

Write a real world problem that involves a percent.

Mathematics
2 answers:
larisa86 [58]4 years ago
6 0
Problem
An estimated
3
33 out of every
2
5
2525 men are left-handed.
never [62]4 years ago
5 0
I'm sorry I didn't see this I don't quite understand it either though :/ sorry
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Hi pls help me guys help me this is my last chance pls guys help Use the data in the table to estimate the likelihood that a per
Sindrei [870]

Answer:

C. The likelihood of having brown eyes is 35%

Step-by-step explanation:

Add the total number of people, which gives you 50.

To find the percent of brown-eyed people out of 50, divide 35 by 50, then multiply the result (0.7) by 100 to get 70%.

70% of people are brown-eyed, thus, C is a false statement.

6 0
2 years ago
Read 2 more answers
To prepare a batch of cookies a factory uses 4/5 barrels of oatmeal in each batch. The factory used 4 4/5 barrels of oatmeal on
babymother [125]

Answer:

Step-by-step explanation:

4 4/5= 24/5  24/5\4/5=6/5= 1/15

6 0
4 years ago
If you were to add all odd numbers between 1 and 11 (both inclusive), the result would be
saveliy_v [14]
The sequence of all odd numbers between 1 and 11 (both inclusive) is
1,3,5,7,9,11

This is an arithmetic sequence with common difference of d=2
The first term is a₁=1.

The number of the term 11 (without counting) is found from
1 + (n-1)*2 = 11
1 + 2n - 2 = 11
2n -1 = 11
2n = 12
n = 6

The sum of the first n terms of an arithmetic sequence is
S_{n} =  \frac{n(a_{1}+a_{n})}{2}

Therefore, the sum of the sequence is
S₆ = [6*(1 + 11)]/2
    = (6*12)/2
    = 36

Answer:  36
3 0
3 years ago
Simplify i^7/i x i^3<br><br><br> A. i^4<br> B.i^11<br> C.i^3<br> D. 1
Liula [17]

Answer:

c.i^ 3

Step-by-step explanation:

i^7/i x i^3

i ^ 7 / i ^ 4

i^ 7 - 4

i^ 3

5 0
3 years ago
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A gardener has 72 feet of fencing to enclose a
ivann1987 [24]

Answer:

p =6w+8=6*(9/3)+8=46 so w =25/3ft and l=44/ 3

Step-by-step explanation:

5 0
4 years ago
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