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just olya [345]
3 years ago
8

What is the value of the x variable in the solution to the following system of equations? 4x − 3y = 3 5x − 4y = 3

Mathematics
1 answer:
andrew-mc [135]3 years ago
5 0
Solve <span>4x − 3y = 3 and  5x − 4y = 3

Step 1: Solve for x in 4x-3y=3:
4x-3y=3
4x-3y+3y=3+3y [Add 3y to both sides]
4x=3y+3
</span>\frac{4x}{4} =  \frac{3x+3}{4} [Divide both sides by 4]
x=\frac{3}{4}y+ \frac{3}{4}

Step 2: Substitute \frac{3}{4}y+ \frac{3}{4}<span> for x in 5x-4y=3
5x-4y=3
5(</span>\frac{3}{4}y+ \frac{3}{4}<span>)-4y=3
</span>\frac{-1}{4}y+ \frac{15}{4}  =3
\frac{-1}{4}y+ \frac{15}{4} - \frac{15}{4} =3- \frac{15}{4} [Subtract \frac{15}{4} to both sides]
\frac{-1}{4}y= \frac{-3}{4}
\frac{ \frac{-1}{4}y}{ \frac{-1}{4} }=  \frac{\frac{-3}{4}  }{ \frac{-1}{4}} [Divide both sides by \frac{-1}{4} ]
<span>y = 3

Step 3: Substitute 3 for y in x = </span>\frac{3}{4}y+ \frac{3}{4}
\frac{3}{4}y+ \frac{3}{4}
\frac{3}{4}(3)+ \frac{3}{4}
x = 3
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CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

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Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

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