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artcher [175]
3 years ago
12

PLEASE HELP ANSWER ASAP

Mathematics
1 answer:
Solnce55 [7]3 years ago
3 0

I cant help you on this if there is no coefficients.

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Answer:

a) The calculated value   t =  5.903 > 2.572 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is a true mean value is less than 10

b) p - value  0.00001

The p - value 0.00001  < 0.01

The result is significant at p<0.01

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given mean of the population = 10

Sample size 'n'= 35

Mean of the sample x⁻ = 14.44

Standard deviation of the sample 's' = 4.45

Level of significance ∝ = 0.01

<u><em>Step(ii)</em></u>:-

<em>Null Hypothesis H₀</em> : μ >10

<em>Alternative Hypothesis</em> : H₁ : μ < 10

Test statistic

                 t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }

                t = \frac{14.44-10}{\frac{4.45}{\sqrt{35} } }

               t =  5.903

Degrees of freedom = n-1 = 35-1 = 34

tabulated value t₀.₀₁,₃₄  = 2.572

The calculated value   t =  5.903 > 2.572 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is a true mean value is less than 10

<u><em>p- value</em></u> :

p - value  0.00001

The p - value 0.00001  < 0.01

The result is significant at p<0.01

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