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artcher [175]
3 years ago
12

PLEASE HELP ANSWER ASAP

Mathematics
1 answer:
Solnce55 [7]3 years ago
3 0

I cant help you on this if there is no coefficients.

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What’s the volume and the question
dalvyx [7]
The formula of the cylindrica's volume is :

V= \pi *r^2*h
V= \pi *1.25^2*4.9
V=24.05281875=24.05

The approximate total volume of the 12 cans would :

V = 24.05*12=288.6= 283 in^3

Therefore, the answer would be the option C.

Hope this helps !

Photon

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3 years ago
Molly had 6 or 33% robins in her yard. Does she need to find a percent, part or whole
Charra [1.4K]

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3 years ago
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2 years ago
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Three semicircles are placed in a rectangle, as shown below. The length of the rectangle is 30 m . Find the area of the shaded r
Anuta_ua [19.1K]

Answer:

The area of the shaded region is: 32.25m^2

Step-by-step explanation:

Given

See attachment for rectangle and semicircles

Required

The shaded region

We have:

l =30 --- length of the rectangle

This means that the diameters of the three circles add up to 30m.

So, the diameter of 1 is:

d = l/3

d = 30/3

d = 10

The area of one circle is:

A_1 = \pi * \frac{d^2}{8}

A_1 = 3.14 * \frac{10^2}{8}

A_1 = 3.14 * \frac{100}{8}

A_1 = 39.25m^2

The area of the three circles is:

A_2 = 3 * A_1

A_2 = 3 *39.25m^2

A_2 = 117.75m^2

The area of the rectangle is:

A_3 = 30 * r

Where r is the radius of the circle

And

r =d/2

r =10/2

r =5

So, we have:

A_3 = 30 * r

A_3 = 30 * 5

A_3 = 150

So, the shaded region is:

A_4 = A_3 - A_2

A_4 = 150 - 117.75

A_4 = 32.25m^2

8 0
3 years ago
Factor 28+56t+28w, to identify the equivalent expressions.
Elodia [21]

Answer:

28(1 + 2t +w)

Step-by-step explanation:

28 + 56t + 28w.

Factor out a 28 from the expression.

28(1 + 2t + w)

8 0
3 years ago
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