The first option,
both have to be negative, because they were originally both part of the one fraction, which was all negative.
<em>⇨ Use the formula below</em>
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<em>⇨ Substitute the parameters:</em>
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Hope that helped
Answer:
yes
Step-by-step explanation:
yes
Answer:
A. -4
Step-by-step explanation:
Given the function f(x) = x + 3 for x ≤ -1 and 2x - c for x > -1, for the function to be continuous, the right hand limit of the function must be equal to its left hand limit.
For the left hand limit;
The function at the left hand occurs at x<-1
f-(x) = x+3
f-(-1) = -1+3
f-(-1) = 2
For the right hand limit, the function occurs at x>-1
f+(x) = 2x-c
f+(-1) = 2(-1)-c
f+(-1) = -2-c
For the function f(x) to be continuous on the entire real line at x = -1, then
f-(-1) = f+(-1)
On equating both sides:
2 = -2-c
Add 2 to both sides
2+2 = -2-c+2
4 =-c
Multiply both sides by minus.
-(-c) = -4
c = -4
Hence the value of c so that f(x) is continuous on the entire real line is -4
Part A: 14 + 14 = y or 14•2 = y
Part B: (n•2) - 2 = a
Not 100% sure that this is correct but, hope this helps! :) If you have any questions than ask me.
