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kolbaska11 [484]
3 years ago
10

Someone plz help me quickkkk

Mathematics
2 answers:
FromTheMoon [43]3 years ago
8 0
It is 80° because 20+60 is 80 also if you look at the whole thing it looks like it is a bit less then 90°
devlian [24]3 years ago
6 0

Answer:

40 because I had the same exact problem and I got an A+

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A pair of coins is tossed. What is the probability of no tails? <br> 0 <br> 1/2 <br> 1/4
lesya [120]
0 cannot be the answer. It makes no sense because you can get a probability of getting tails when flipping a coin.

The answer would be 1/2. You have '2' choices (heads or tails) and 1 out of those 2 times would you possibly get tails.
4 0
3 years ago
Read 2 more answers
3
nikitadnepr [17]

Answer:

sry I just wanted the points I'm in middle school so I don't know this stuff either but can you give free brainlyest I'm soo close to my next rank I'd really appreciate it if you would

7 0
3 years ago
23 over.30 ÷20 over 24
alexgriva [62]

Remark

Don't try and do this all at once. Break it down, otherwise you'll have layers and brackets all over the place.

Step One

Find 23/0.3

X = 23/0.3 = 76.7

Step Two

Now Divide by 20

x1 = 76.7 / 20

x1 = 3.83

Step Three

Take this result and put it over 24

x2 = x1/24

x2 = 3.83 / 24

x2 = 0.1597 <<<< Answer

6 0
3 years ago
Read 2 more answers
Solve. 15 − 6(x + 1) = 12<br> Help nowwwww
Gekata [30.6K]

Answer:

Your answer would be 2

Step-by-step explanation:

15 - 6(x+1) =12

15- 6*x +6*1 = 12

15 - 6x + 6 = 12

15 - 6 + 6x = 12

9 + 6x = 12

9 - 9 + 6x = 12 - 9

6x = 3

x = 2

5 0
4 years ago
Estimate the perimeter and area of the shaded figure to the nearest tenth.
Maru [420]

Answer:

Perimeter = 18.7 units

Area = 13.5 units²

Step-by-step explanation:

Perimeter of ADEC = AD + DE + EC + AC

Length of AD = 3 units

By applying Pythagoras theorem in ΔDBE,

DE² = DB² + BE²

DE² = 3² + 3²

DE = √18

DE = 4.24 units

Length of EC = 3 units

By applying Pythagoras theorem in ΔABC,

AC² = AB² + BC²

AC² = 6² + 6²

AC = √72

AC = 8.49 units

Perimeter of ADEC = 3 + 4.24 + 3 + 8.49

                                 = 18.73 units

                                 ≈ 18.7 units

Area of ADEC = Area of ΔABC - Area of ΔBDE

Area of ΔABC = \frac{1}{2}(AB)(BC)

                       = \frac{1}{2}(6)(6)

                       = 18 units²

Area of ΔBDE = \frac{1}{2}(BD)(BE)

                       = \frac{1}{2}(3)(3)

                       = 4.5 units²

Area of ADEC = 18 - 4.5

                        = 13.5 units²

6 0
3 years ago
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