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Andru [333]
3 years ago
10

What is the value of y?

Mathematics
2 answers:
Pavel [41]3 years ago
6 0
Y = (180-72)/2 = 54°
-BARSIC- [3]3 years ago
6 0
Your answer would be B. 54 degrees. Hope I helped! 
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The Pythagorean theorem is a² + b² = c². Solve for b. b=±c+a−−−−√ b=±c2−a2−−−−−−√ b=±c2+a2−−−−−−√ b=±c−a−−−−√
uysha [10]

a^{2} +b^{2} =c^{2}

As we have to solve for b, it means we have to isolate b

So first of all subtract a^{2} from both sides

So we get

b^{2} =c^{2} -a^{2}

Now we need b , but its b^2 , so we can take square root on both sides.


taking square roots on both sides

b= +- \sqrt{c^2 -a^2}


Hence option B is correct

4 0
3 years ago
Find the slope and Y intercept for each equation y=2x -4
kifflom [539]
The y intercept is -4 and the slope is 2
6 0
3 years ago
Read 2 more answers
((Image Included))
Bas_tet [7]

Answer:

=204.13 inches.

Step-by-step explanation:

Using the side x, we can use sine to find the hypotenuse of the triangle with the angle marked 30°.

Sin 30 =x/hypotenuse.

sin 30 = 27/hyp

hyp= 27/sin 30

=54 inches

We can also find the adjacent as follows.

Cos 30 = adjacent/ 54

Adjacent= 54 cos 30

=46.77 inches

Using the angles marked 45 we can find the hypotenuse of the isosceles triangle.

sin 45= x/hypotenuse

sin 45 =27/hypotenuse

hypotenuse = 27/sin 45

=38.18 inches

The hypotenuse of both the triangles making the isosceles triangle are 38.18 inches long.

Perimeter = 54+ 46.77+27+ 38.18+38.18

=204.13 inches.

6 0
2 years ago
Read 2 more answers
F(x) = 5x - 3 for x = -7
erastovalidia [21]

Answer:

Step-by-step explanation:

f(-7) = 5(-7) - 3 = -35 - 3 = -38

6 0
3 years ago
A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides
ivolga24 [154]

Answer:

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

Step-by-step explanation:

Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

                                                         =(15-2x)(10-2x)x cubic inches

                                                         =(150x-50x²+4x³) cubic inches

∴ V= 4x³-50x²+15x

Differentiating with respect to x

V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

For maximum or minimum value, V'=0

12x²-100x+15=0

Apply quadratic formula x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}, here a=12, b= -100 and c=15

x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}

\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}

\Rightarrow x=0.1528,8.18

For x= 8.18, The value of (15-2x) and (10-2x) will negative.

∴x=0.1528 .

Now, V''|_{x=0.1528}=24(0.1528)-100

∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

4 0
3 years ago
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