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Ksenya-84 [330]
3 years ago
13

you lease a car valued at 23,495 for 3 years at $429.95/month with a $500 down payment. If interest is 30% of the payment, how m

uch interest is paid over the 3 years?
Mathematics
2 answers:
Monica [59]3 years ago
7 0
(36 payments)*($429.95)*30% = $4,643.46 . . . . interest paid over 3 years
olasank [31]3 years ago
5 0

Solution:

Present Value of car= $ 23,495

Down Payment = $ 500

Total Amount paid monthly for 3 years that is 36 months, if you pay $ 429.95 per month=$ 15478.20

Total amount paid for the car as an agreement which includes Down payment of $ 500 as well as monthly Payment of $ 429.95 for 36 months= $ 15478.20+$ 500=$ 15978.20

As, given Interest is  30% of the payment.

So, total interest = 30% of $ 15978

=\frac{30}{100}\times 15978.20

= $ 4793.40

But if you will calculate interest on payment of $ 429.95 at the rate of 30%, it gives

=\frac{30}{100}\times 429.95

= $128.985

So, total interest for 3 years= $128.985 ×36=$ 4643.46

Also, if you will calculate interest on payment of ($500+$429.95=$929.95) at the rate of 30%

=\frac{30}{100}\times 929.95

=$278.985

Total interest for 3 years= $278.985 ×36=$10,043.46

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4 0
3 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3


has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
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According tot he rational root theorem, which statement about f(x)=12x^3-5x^2+6x+9 is true?
vampirchik [111]

Answer:

If there are any rational roots, it would be a factor of your constant term (9) divided by a factor of the high-order coefficient (12).

3 0
3 years ago
Anyone know the answer to this ??
lana [24]
Answer: 23%
explanation:
4 + 6 + 2 + 2 + 3 + 4 + 6 + 3
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Round to nearest whole percent.
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