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Rina8888 [55]
3 years ago
10

The probability that a randomly-selected person at a show has seen the band play live before is 50%. A "superfan" is defined as

someone who has seen the band play live at least 5 times. The probability that a person at a show is a "superfan" is 30%. Two people are selected at random. What is the probability that both people have both seen the band perform live before, and are "superfans?"
Mathematics
1 answer:
zavuch27 [327]3 years ago
4 0

Answer:

0.25 and 0.09

Step-by-step explanation:

The probability that a randomly-selected person at a show has seen the band play live before is 50%=0.50

The probability that a person at a show is a "superfan" is 30%=0.30

Two people are selected at random.

The probability that both people have both seen the band perform live before

= The probability that the first person has seen the band live before and the second person also has seen the band live before.

=0.50 x 0.50

=0.25

Similarly, the probability that both are  "superfans"

=The probability that the first person is a superfan and the probability that the second person is a superfan.

=0.30 x 0.30

=0.09

Hence, the probability that both people have both seen the band perform live before, and are "superfans" are 0.25 and 0.09 respectively.

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Weights of American adults are normally distributed with a mean of 180 pounds and a standard deviation of 8 pounds. What is the
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Answer:

15.87% probability that a randomly selected individual will be between 185 and 190 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 180, \sigma = 8

What is the probability that a randomly selected individual will be between 185 and 190 pounds?

This probability is the pvalue of Z when X = 190 subtracted by the pvalue of Z when X = 185. So

X = 190

Z = \frac{X - \mu}{\sigma}

Z = \frac{190 - 180}{8}

Z = 1.25

Z = 1.25 has a pvalue of 0.8944

X = 185

Z = \frac{X - \mu}{\sigma}

Z = \frac{185 - 180}{8}

Z = 0.63

Z = 0.63 has a pvalue of 0.7357

0.8944 - 0.7357 = 0.1587

15.87% probability that a randomly selected individual will be between 185 and 190 pounds

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If he uses 1 quarter, he has 40 cent left to make.He can do that in two ways, by using 2 dimes andall four nickels, or all 3 dimes snd 2 nickels.That's 2 ways.
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Lee records the height of players on a basketball team and calculates the mean absolute deviation of the set of data.
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3 years ago
What is the code? Thank you! Whoever answers this, I will give brainliest!
shepuryov [24]

Answer:

5821

Step-by-step explanation:

For the first symbol, the number is 5.

In the first problem, the digit corresponding to that symbol is 5.

In the second one, it should be 5. The area of a triangle is base * height / 2. The base is 15 and the height is 9. Therefore, the area will be 15 * 9 / 2 = 67.5 square units. Now, the number corresponding to that symbol is 5.

In the fourth problem, the number corresponding to the symbol is also 5.

For the second symbol, the number is 8.

In the 5th problem, the number corresponding to that symbol is 8.

In the 7th problem, the number corresponding to the symbol is 8.

In the last problem, 96 is the correct answer, and everything is in the right place. I assume this must be the mistake of the maker of the problem.

For the third symbol, the number is 2

In the 1st and 3rd problems, the number corresponding to that symbol is 2

Finally, for the last symbol, the number is 1

In the 4th problem, there is a trapezoid. The formula for the area of a trapezoid is base 1 * base 2 / 2 * height. base 1 = 29, base 2 = 13. 13 + 29 = 42. 42 / 2 = 21. 21 * 15 = 315. Now, the 2nd digit, the one corresponding to the symbol, is 1.

In the last problem, you need to find the surface area of a figure. I would do this by splitting it up. The area for a triangle is base * height / 2. That means, the area of the triangle would be 8 * 7 / 2 = 28. There are four identical triangles, so you multiply this by 4 and get 112. Next, you find the area of the square which is 7 * 7. 7 * 7 = 49. Now, you add them together. 112 + 49 = 161. Now, the first and last digits corresponding to the symbol are both 1.

The answer is 5821.

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