I need this answer as fast as i can get it

Mathematics

2 answers:

Aliun [14]3 years ago

7 0

Answer:

Step-by-step explanation:

2/9 is closer to 0 and 10/11 is closer to 1 so it would be D

Stella [2.4K]3 years ago

4 0

Answer:

Try B. I believe that is the answer

Explanation:

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The difference between two numbers is 7194. If the subtrahend is 12,806, find the minuend.

valentina_108 [34]

<u>Answer:</u> The minuend is 20000

<u>Step-by-step explanation:</u>

To calculate the minuend, we use the equation:

$\text{Subtrahend}=\text{Minuend-Difference}$

We are given:

Difference between the two numbers = 7194

Subtraend = 12806

Putting values in above equation, we get:

$\text{Minuend}=12806+7194\\\\\text{Minuend}=20000$

Hence, the minuend is 20000

3 0

3 years ago

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$