Solving for x would give me 14 and negative 10 which would lead to the problem looking like so 14(-10-4)=140
We Can Let "A Number" Be M.
M Divided By 3 Less Than Itself Gives Quotient Of 8/5.
M/(M-3) = 8/5. Lets Solve.

So, What Number Can Have 3 Subtracted From It To Get Five, But Also Be Equal To Eight?
Eight Of Course!!!
So, We Know That The Number Equals 8.
Answer:
{0,6}
Step-by-step explanation:
-2x^2+12x = 0
Factor out a -2x
-2x(x-6) =0
Using the zero product property
-2x = 0 and x-6=0
-2x = 0
Divide by -2
-2x/-2 = 0/-2
x=0
x-6=0
Add 6 to each side
x-6+6 =0+6
x=6
The solutions are 0 and 6
-3/4 goes between -1 and 0 it is the 3rd line to the left and n would go between positive 0 and 1 on the 3rd line to the right
<h3>
Answer: choice 4. f(x) and g(x) have a common x-intercept</h3>
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Explanation:
For me, it helps to graph everything on the same xy coordinate system. Start with the given graph and plot the points shown in the table. You'll get what you see in the diagram below.
The blue point C in that diagram is on the red parabola. This point is the x intercept as this is where both graphs cross the x axis. Therefore, they have a common x intercept.
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Side notes:
- Choice 1 is not true due to choice 4 being true. We have f(x) = g(x) when x = 2, which is why f(x) > g(x) is not true for all x.
- Choice 2 is not true. Point B is not on the parabola.
- Choice 3 is not true. There is only one known intersection point between f(x) and g(x), and that is at the x intercept mentioned above. Of course there may be more intersections, but we don't have enough info to determine this.