All categories

3 years ago

Which one of the following statements expresses a true proportion?

1 answer:

3 0

Try them step by step

2/3=3/2? No

3/5=12/20? Lets try and see

If we simplify 12/20 what do we do? Well we take 4*3=12 and 4*5=20

Now that we simply the 4 from both the numerator and denominator we get our answer 3/5

Your answer will be B.

You might be interested in

Evaluate 3|-4| 12 4 -12

jeka94

Answer:

Step-by-step explanation:

Absolute value means take the positive value

3|-4|

3*4

5 0

3 years ago

Read 2 more answers

Ann's first option is a plot of land adjacent to a current park.

oksian1 [2.3K]

Given:

The equation for the area of the first option is:

$x^2+200x=166400$

Where x is the side length of the current square park.

To find:

The side length of the current square park.

Solution:

We have,

$x^2+200x=166400$

It can be written as:

$x^2+200x-166400=0$

Splitting the middle term, we get

$x^2+520x-320x-166400=0$

$x(x+520)-320(x+520)=0$

$(x-320)(x+520)=0$

$x=320,-520$

We know that the side length of a park cannot be negative. So, the only possible value of x is 320.

Therefore, the most direct method to solve the given equation is splitting the middle term and the side length of the current square park is 320 meters.

4 0

2 years ago

Mable has 185 dollars worth of apples. Each apple is worth more then 3 dollars but less then 10 dollars. The number has four let

velikii [3]

Answer:

The worth of each of Mable's apples is $5

Step-by-step explanation:

Extracting the key information from the question:

***Mable has apples that are worth a combined 185 dollars.

*** One apple from Mable's apples worth more than three ($3) dollars but less than ten ($10) dollars.

***The cost of one apple is a number that has four letters.

*** That number (the cost) of one apple is also a prime number.

*** We are required to find or determine the worth of one of Mable's apples.

Now, one of the clues given to us which we may use to figure out the cost or worth of one apple is that the apple is worth more than three dollars ($3) but worth less than ten dollars ($10). This means that each Mable's apple may worth $4 or $5 or $6 or $7 or $8 or $9. That is one of Mable's apples worth from $4 to $9

Another clue to solving this puzzle is that the worth of one apple in dollars is a prime number. This implies that one of Mable's apples may worth either five dollars ($5) or seven dollars ($7).

The next clue for unravelling this mystery is that all Mable's apples are worth a combined $185. This then means that the worth of each apple (the number) must be able to divide 185.

Since $7 and $5 are the only two figures left standing, we will then try and see which one of them will be able to do divide the number "185".

185/7 = 26 remainder 3

185/5 = 37 remainder 0

The final clue in the question is that the worth of each of Mable's apples is a figure/number that has only letters:

$7 SEVEN has = 5 letters

$5 FIVE has = 4 letters

This now brings us to the conclusion that the worth of each of Mable's apples is five dollars ($5) since it meets all the requirements and clues in the question.

6 0

3 years ago

Help i cant get this wrong

pashok25 [27]

Answer:

Step-by-step explanation:

I'm not the greatest in this subject, but I think that it's D/If the roof leaks, then the ceiling gets damaged because it clearly says that in the statement. It could be all of them, though, but this is my answer. Hope it helps!

8 0

3 years ago

Read 2 more answers

How many 3 digit numbers are possible when a) the leading digit cannot be zero and the number must be a multiple of 4?

guajiro [1.7K]

Step-by-step explanation:

I assume the digits can be repeated.

so, e.g. 555 is a valid number for this problem, right ?

that means we start with permutations with repetition :

n^r

n = the total number of items to pick from.

r = the number of items being picked per result.

we have 10 digits (0,1,2,3,4,5,6,7,8,9), and we pick 3 of them.

that gives us (with very little surprise, I hope)

10³ = 1000 different possible numbers from 000 to 999.

from these numbers we eliminate all with leading 0.

as we handled all digits the same way and with the same priority, there is the same amount of numbers for every digit in the leading position.

that means 1/10 of the total amount of numbers has a leading 0, or a leading 1, or a leading 2, ...

so, we need to subtract 1/10 × 1000 from 1000 :

1000 - 1000×1/10 = 1000 - 100 = 900

that would be the numbers 100 to 999.

and we have one more condition : the number must be a multiple of 4.

how many are there ?

well, that's the funny thing about numbers : from all numbers 1/2 of them are multiples of 2 (or divisible by 2), 1/3 of them are multiples of 3 (or divisible by 3), and ... you guessed it, 1/4 of them are multiples of 4 (or divisible by 4). and so on.

and so, 1/4 of our 900 numbers are multiples of 4 :

1/4 × 900 = 225

so, there are 225 possible 3-digit numbers that are multiples of 4 and do not start with a 0.

6 0

2 years ago