Answer:
-1 and 0
Step-by-step explanation:
X ^4+x = 0;
x*(x^3+1)=0;
x*[(x^3-x)+(x+1)]=0;
x*[x(x-1)(x+1)+(x+1)]=0;
x*(x+1)(x^2-x+1)=0;
Since x^2-x+1=0 has no intersection with the X-axis, there is no x value such that y=0
x=0 or -1
Answer:
33% (B)
Step-by-step explanation
It increased by 150, and 150 is 1/3 of 450, so 33% Hope this helped! Good luck!
Answer:
y^7
Step-by-step explanation:
y^3 . y^5 . y^-2 . y
= y^3 . y^5 . y^-2 . y^1
= y^( 3 + 5 - 2 + 1 )
= y^( 3 + 5 + 1 - 2 )
= y^( 9 - 2 )
= y^7
Answer:
(x, y) = (1, 1)
Step-by-step explanation:
Using the second equation to substitute for y in the first equation, we have ...
x = -2x +3
3x = 3 . . . . . . . add 2x
x = 1 . . . . . . . . .divide by 3
y = x = 1
The solution is (x, y) = (1, 1).
_____
If you have the graph, you can read the solution from it as the coordinates of the point where the lines cross.
Step-by-step explanation:
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