Answer:
1.39
Step-by-step explanation:
Creating a table:
X :___0 __ 1 __ 2 ___ 3 ____ 4 ___ 5 ___ 6
P(x):0.02_0.03_0.07, 0.12, 0.30_ 0.28_0.18.
The standard deviation = sqrt(Var(x))
Var(x) = Σx²*p(x) - E(x)²
E(x) = ΣX*p(x)
E(x) = (0*0.02) + (1*0.03) + (2*0.07) + (3*0.12) + (4*0.30) + (5*0.28) + (6*0.18) = 4.21
Var(X) :
((0^2*0.02) + (1^2*0.03) + (2^2*0.07) + (3^2*0.12) + (4^2*0.30) + (5^2*0.28) + (6^2*0.18)) - 4.21^2
19.67 - 17.7241
= 1.9459
Standard deviation = sqrt(Var(X))
Standard deviation = sqrt(1.9459)
Standard deviation = 1.3949551
= 1.39
I think the correct answer is A. Hope this helps.
-5 like minus 5 no mater the negetive for y
Hope this helped ")
18b^2 : 45b
Divide by 3b
6b : 15
Divide by 3
2b : 5
