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monitta
3 years ago
8

Find the horizontal and vertical asymptotes of​ f(x). ​f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the

horizontal asymptotes. Select the correct choice below and fill in any answer boxes within your choice. A. The horizontal​ asymptote(s) can be described by the​ line(s) nothing . ​(Type an equation. Use a comma to separate answers as​ needed.) B. There are no horizontal asymptotes. Find the vertical asymptotes. Select the correct choice below and fill in any answer boxes within your choice. A. The vertical​ asymptote(s) can be described by the​ line(s) negative 2 −2 . ​(Type an equation. Use a comma to separate answers as​ needed.) B. There are no vertical asymptotes.
Mathematics
2 answers:
miss Akunina [59]3 years ago
6 0

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* <em>Lets the meaning of vertical and horizontal asymptotes</em>

- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes

  of the denominator of a rational function

- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function

 approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

 denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

 denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

 then there is a horizontal asymptote at y = leading coefficient of the

 numerator ÷ leading coefficient of the denominator

* <em>Lets solve the problem</em>

∵ f(x)=\frac{6x}{x+2}

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ <em>The horizontal asymptote can be described by the line y = 6</em>

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ <em>The vertical asymptote can be described by the line x = -2</em>

Rudiy273 years ago
4 0

Answer:

horizontal asymptote at y = 2, vertical asymptote at x = 1

Step-by-step explanation:

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Which of the following describes the graph of y = x² - 225?
lara [203]

Answer:

option 4. The graph has zeroes at x = 15 an x = -15 and it opens upward.

Step-by-step explanation:

we have

y=x^{2} -225

This is the equation of a vertical parabola open upward (the leading coefficient is positive)

The vertex represent a minimum

The vertex is the point (0,-225)

The axis of symmetry is x=0 (y-axis)

Find the x-intercepts (values of x when the value of y is equal to zero)

For y=0

0=x^{2} -225\\x^2=225

square root both sides

x=\pm15

therefore

The graph has zeroes at x = 15 an x = -15 and it opens upward.

3 0
3 years ago
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6 0
3 years ago
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yulyashka [42]

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4 years ago
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Step-by-step explanation:

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sukhopar [10]
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Hoped this helped!
3 0
3 years ago
Read 2 more answers
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