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3 years ago

I need help with 9-11 shown above in the picture. Please explain if you can

Mathematics

1 answer:

Lunna [17]3 years ago

8 0

Its telling you how many marbles there are and the coler that be used on 9-11 ,its asking you to find the outcome same with 10,now 11 describe the scoring and how its a fair game if you need aswere let me know and i help with them

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What is the messure of N and the two angles; an-16 and 6n

AURORKA [14]

Answer:

14, 96,84

Step-by-step explanation:

8n - 16 + 6n = 180 {Supplementary angles}

<u>8n + 6n</u> -16 = 180

Combine like terms

14n - 16 = 180

Add 16 to both sides

14n = 180 + 16

14n = 196

Divide both sides by 14

n = 196/14

n = 14

8n - 16 = 8*14 - 16 = 112 - 16 = 96

6n = 6 *14 = 84

7 0

2 years ago

A horse's resting heart rate is

DIA [1.3K]

<span>The pulse rate of an adult horse at rest averages 30-40 beats per minute.</span>

4 0

3 years ago

Read 2 more answers

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

2 years ago

If x = 5 & y = 3 what is 3x + 5y?

notka56 [123]

Answer:

Step-by-step explanation:

If you plug in 5 for x and 3 for y then the equation would be 3(5)+5(3) or 15+15.

4 0

2 years ago

Can someone help me out with this at all?

dsp73

Answer:

1 maps to 1

2 maps to 3

3 maps to 2

Step-by-step explanation:

the correctly assigned answer options describe everything.

there is not much else to say and explain.

these are all true statements due to the symmetry principle of a circle.

when 2 direct connections of two points on the circumference of a circle have the same length, then also their bent distances on the circumference of the circle are the same. and vice versa.

and yes, the perpendicular radius (or diameter) of the circle towards such a line cuts this line in half.

6 0

2 years ago