Question

(3+i)^2 = c+di, find the value of d.

Answer 1

Answer:

d. $\displaystyle 6$

Step-by-step explanation:

$\displaystyle [3 + i]^2 = [3 + i][3 + i] = 9 + 6i + i^2 → 9 + 6i - 1 → 6i + 8$

Therefore, the d-value is 6.

Extended Information on the Complex Number System

$\displaystyle \sqrt{-1} = i \\ -1 = i^2 \\ -i = i^3 \\ 1 = i^4\:[every\:multiple\:of\:4]$

I am joyous to assist you anytime.