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3 years ago

Please help I will give brainlesstQuestion 9 of 10

Mathematics

1 answer:

inessss [21]3 years ago

8 0

Answer: D, x^3 (x-7)

Step-by-step explanation:

plug into G(f(x))

x^3 (x - 7)

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Given the angle 1=2x+35 and the angle 2=3x+7. Find the angle measures

user100 [1]

tiene que copiar sii el primero y segundo todos

8 0

4 years ago

7x+3y=-12 2x+5y=38<br> Please help

VikaD [51]

7x + 3y = -12
2x + 5y = 38
5y = -2x + 38
y = -2x/5 + 38/5
7x + 3•(-2x/5+38/5) = -12
29x/5 = -174/5
29x = -174
x = - 6
x=-6
y = -2x/5+38/5
y = -(2/5)(-6)+38/5 = 10
x=-6
y=10

5 0

4 years ago

Owen plans to deposit $4000 in a traditional IRA at the end of every six months for the next 10 years find the future value if f

Mila [183]

800$ because yearly he would deposit 8000$ and 10% of that would be 800$ :)

4 0

3 years ago

Use 3.14 for pi. Round to the nearest tenth

V125BC [204]

Answer:

$\boxed{\text{\sf \Large 138.6 mm^2 $}}$

Step-by-step explanation:

Area of rectangle

$15 \times 5=75$

Area of circle (semi-circle+semi-circle)

$r=(15-3-3) \div 2 = 4.5$

$\pi \times 4.5^2=20.25\pi$

Add both areas

$20.25\pi +75$

$20.25 \times 3.14 +75=138.585$

6 0

3 years ago

Please help need ASAP

victus00 [196]

Answer: Approximately 12719 feet

===========================================================

Explanation:

See the diagram below.

We have the following points

A = Plane's location.
B = car #1's location.
C = car #2's location .
D = point directly above point B (same horizontal level as point A).
E = point directly above point C (same horizontal level as point A).

The goal is to find the length of segment BC, which is the distance between the two cars. For now, let's call it x.

Note how quadrilateral BCED is a rectangle. This means that the opposite sides BC and ED are the same length. Furthermore, note how segment ED is broken up into DA and AE, which I'll call m and n.

So we have these variable assignments

x = length of segment BC
m = length of segment DA
n = length of segment AE

We'll find the values of m and n, so we can then find the value of x. We can see that x = m+n.

---------------

Let's focus entirely on triangle ABD

Apply a tangent ratio to solve for m

tan(angle) = opposite/adjacent

tan(A) = BD/AD

tan(32) = 5150/m

m*tan(32) = 5150

m = 5150/tan(32)

m = 8241.7228245614

This value is approximate. Make sure your calculator is in degree mode.

We'll come back to this later.

---------------

Now focus entirely on triangle CEA. We'll apply the tangent rule again.

tan(angle) = opposite/adjacent

tan(A) = EC/AE

tan(49) = 5150/n

n*tan(49) = 5150

n = 5150/tan(49)

n = 4476.82669975357

This value is approximate.

---------------

Now we can find x.

x = m+n

x = 8241.7228245614 + 4476.82669975357

x = 12718.549524315

x = 12719

The distance between the two cars is roughly 12719 feet

I'm rounding to the nearest whole number because the other values were given to be whole numbers.

Side note: 12719 ft = 2.41 miles approximately (divide by 5280 to convert from feet to miles).

3 0

3 years ago