The setup boxes in the synthetic division are (b)
<h3>How to determine the setup boxes?</h3>
The dividend is given as:
x^3 + 4x^2 + x - 6
The divisor is given as:
x - 2
Set the divisor to 0
x - 2 = 0
Solve for x
x = 2
Remove the variables in the dividend
1 + 4 + 1 - 6
Remove the arithmetic signs
1 4 1 - 6
So, the setup is:
2 | 1 4 1 - 6
Hence, the setup boxes are (b)
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Answer:
its probably 6×2=12 times
coin has 2 sides
dice has 6 faces
The answer is -4 i just did the test
Wait is it not at all 14.5 or 14 1/2 Because with the math I did I got 14 1/2
25%
since there are 4 books, and only one is a mathematics book, there is a 1/4 chance. in other words, 25%
