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alexandr402 [8]
4 years ago
12

Can anyone help with this domain and range? Thank you!

Mathematics
1 answer:
nydimaria [60]4 years ago
5 0

Answer:

both are all real numbers. hope i helped!!

:)

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Answer:

\Large \boxed{\sf \ \ f^{-1}(x)=x^2-3 \ \ }

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Hello,

\text{For }x+3\geq 0\\\\f(x)=\sqrt{x+3}\\\\x=(fof^{-1})(x)=f(f^{-1}(x))=\sqrt{f^{-1}(x)+3}\\\\\text{*** take the square ***}\\\\f^{-1}(x)+3=x^2\\\\\text{*** subtract 3 from both sides ***}\\\\\large \boxed{\sf \ \ f^{-1}(x)=x^2-3 \ \ }\\

Hope this helps.

Do not hesitate if you need further explanation.

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