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Eduardwww [97]
3 years ago
8

If f(x) = square root of x+3, what is the equation for f–1(x)? f–1(x) = x2 - 3 f–1(x) = x2 + 3 f–1(x) = (x - 3) 2 f–1(x) = (x +

3) 2
Mathematics
1 answer:
cupoosta [38]3 years ago
3 0

Answer:

\Large \boxed{\sf \ \ f^{-1}(x)=x^2-3 \ \ }

Step-by-step explanation:

Hello,

\text{For }x+3\geq 0\\\\f(x)=\sqrt{x+3}\\\\x=(fof^{-1})(x)=f(f^{-1}(x))=\sqrt{f^{-1}(x)+3}\\\\\text{*** take the square ***}\\\\f^{-1}(x)+3=x^2\\\\\text{*** subtract 3 from both sides ***}\\\\\large \boxed{\sf \ \ f^{-1}(x)=x^2-3 \ \ }\\

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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1/4+2/3-1/2= how do I solve this
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Answer:

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Step-by-step explanation:

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Then you need to do the same to 2/3. This time you need to multiply it by 4/4 to get the same denominator which will be 2/3*4/4=8/12

Then you add 3/12+8/12=11/12. You don't need to add the denominator.

After this you will need to subtract 11/12 and 1/2. This time you need to only change the denominator for 1/2.

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3 years ago
I need to be walked through this please.
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Https://us-static.z-dn.net/files/dd1/572d05be5373c1dc9c067ca6690a41a1.jpeg

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4 years ago
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Step-by-step explanation:

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3 years ago
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Find the equation of the tangent line at the point (1, 6). for y = 4 + 4x2 - 2x3.
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<h3><u>☁ Problem:</u></h3>

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<h2>-HunnyPeachy</h2>

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