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Eduardwww [97]
3 years ago
8

If f(x) = square root of x+3, what is the equation for f–1(x)? f–1(x) = x2 - 3 f–1(x) = x2 + 3 f–1(x) = (x - 3) 2 f–1(x) = (x +

3) 2
Mathematics
1 answer:
cupoosta [38]3 years ago
3 0

Answer:

\Large \boxed{\sf \ \ f^{-1}(x)=x^2-3 \ \ }

Step-by-step explanation:

Hello,

\text{For }x+3\geq 0\\\\f(x)=\sqrt{x+3}\\\\x=(fof^{-1})(x)=f(f^{-1}(x))=\sqrt{f^{-1}(x)+3}\\\\\text{*** take the square ***}\\\\f^{-1}(x)+3=x^2\\\\\text{*** subtract 3 from both sides ***}\\\\\large \boxed{\sf \ \ f^{-1}(x)=x^2-3 \ \ }\\

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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pochemuha

Answer: 109.1 degrees

Step-by-step explanation:

To find the angle between the given vectors, we will use the formula below:

Cos(θ) = (U.V)/ |U|.|V|

Where

U = 13i - 8j

V = 2i + 9j

U.V = (2x13) + (-8×9)

U.V = 26 - 72

U.V = - 46

|U| = sqrt ( 13^2 + 8^2)

= sqrt ( 233) = 15.264

|V| = sqrt( 2^2 + 9^2)

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Substitute all the value of the parameters into the formula

Cos ø = -46 / (15.3 × 9.2)

Cos ø = - 46 / 140.72

Cos Ø = - 32687

Find the cos inverse of the value

Ø = cos^-1( -32687)

Ø = 109.079 degrees

Therefore, the angle between the given vectors to the nearest tenth of a degree is 109.1 degrees

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3 years ago
A right triangle has legs of length 4x and 20x. What is an expression for the hypotenuse of the right triangle
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Answer:

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Step-by-step explanation:

Given information:

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According to the Pythagoras theorem,

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Using Pythagoras theorem, we get

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Taking square root on both sides.

hypotenuse=\sqrt{416x^2}

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Step-by-step explanation:

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