3 years ago

What is value of sin2npi

1 answer:

7 0

$n=0\to\sin(2\cdot0\pi)=\sin0=0\\\\n=1\to\sin(2\cdot1\pi)=\sin2\pi=0\\\\n=2\to\sin(2\cdot2\pi)=\sin4\pi=0\\\vdots\\\sin2n\pi=0\ for\ n\in\mathbb{Z}$

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