Given:
Size of a red blood cell = 0.000007 m
Size of a plant cell = 0.0000127 m
To find:
The comparison of these two values.
Solution:
We have,
Size of a red blood cell = 0.000007 m
Size of a plant cell = 0.0000127 m
Clearly, 
. Now, the difference between these two values is:
Therefore, the size of a plant cell is 0.0000057 m more than the size of a red blood cell.
V = s^2 +1/2sh
Reorder so common terms are on one side.
s^2 +(sh)/2 = v
Subtract s^2 from both sides.
(sh)/2 = -s^2 +v
Multiply both sides of the equation by 2.
sh = -s^2 *2 +v *2
Simplify each term.
sh = -2s^2 +2v
Divide each term by s and simplify.
h = -2s + (2v)/s
Part (a)
The picture alone, without the frame, is 16 by 20
When accounting for the frame, the larger rectangle is 16+2x by 20+2x
We add up all four sides to get the perimeter
(16+2x)+(20+2x)+(16+2x)+(20+2x)
8x+72
or you can use this perimeter of a rectangle formula
P = 2(L+W)
P = 2(20+2x+16+2x)
P = 2(4x+36)
P = 8x+72
Answer: 8x+72
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Part (b)
Multiply the length and width to find the area of the rectangle.
area = length*width
A = L*W
A = (20+2x)*(16+2x)
A = 20(16+2x) + 2x(16+2x)
A = 320+40x + 32x + 4x^2
A = 4x^2 + 72x + 320
Answer: 4x^2 + 72x + 320
=========================================
Part (c)
Plug x = 2 into the perimeter equation found in part (a)
P = 8x+72
P = 8*2+72
P = 16+72
P = 88
Now plug x = 2 into the area equation found in part (b)
A = 4x^2 + 72x + 320
A = 4(2)^2 + 72(2) + 320
A = 4(4) + 72(2) + 320
A = 16 + 144 + 320
A = 160+320
A = 480
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Answers:
Perimeter = 88 inches
Area = 480 square inches
To start, let x represent the width and x+100 represent the length.
Since the perimeter of a figure is the sum of all the measurements of the side which can be represented by (x+100)+(x+100)+x+x and since you know your perimeter is 960 feet, you can set the expression equal to 960. This would look like this:
(x+100)+(x+100)+x+x=960
Once you have done that, combine any like terms (combine terms with the same variables and raised to the same power together) which would simplify to this:
4x+200=960
Now that you have your like terms simplified, subtract 200 from both sides to get 4x=760 and finally, to solve for x, or find the width, divide both sides by 4 to get x=190.
Now that you have your width, now you must find your length as the question asks to find the dimensions of the rectangular field. To find the length, add 100 to the width of (190) since according to the information given, the length is 100 more than the width. When you add 100 to 190, you should get that your length is 290.
Now that you have your length and width, you can conclude that the dimensions of the field is 190 by 290 feet, which is your answer :)
They are at the 31 yard line
