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3 years ago

Can anyone help it would mean alot im struggling right now

Mathematics

1 answer:

Setler79 [48]3 years ago

6 0

Answer:

what do you need? ^-^ I can help you

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Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

3 years ago

The table represents the total miles traveled, y, after a number of hours, x.

Annette [7]

60x=y

To find this answer, find what y/x=m would be for m
150/2.5=60
240/4= 60
330/5.5=60
420/7=60

3 0

3 years ago

Read 2 more answers

10 families were asked how many pets they have.here i8s the data.2,3,3,5,4,2,4,0,1,3 find the mean ,medianand mode of the data?

VladimirAG [237]

The mean is 2.7.
The median is: 3
The mode is 3.
Hope this helps!
pls give Brainliest answer!
p.s. if you need an explanation of how to find the mean, median, and mode, just pm me.

4 0

3 years ago

Read 2 more answers

There are four blue marbles, an unknown number of red (r) marbles, and six yellow marbles in a bag. Which expression represents

MAXImum [283]

Answer:

There are a total of 4 + r + 6 marbles in the bag

The probability of a blue is $\frac{4}{10+r}$

The probability of a red is $\frac{r}{10+r}$

The probability of choosing a blue, replacing it and then a red is

$\frac{4}{10+r}$ × $\frac{r}{10+r}$ = [tex]\frac{4r}{100+20r+ r^{2} /[tex]

Step-by-step explanation:

6 0

3 years ago

Solve r = 4/3(p-q) for p

ddd [48]

Answer:

q+3/4r=p

Step-by-step explanation:

r=4/3(p-q)

Distribute the 4/3

r=4/3p-4/3q

Add 4/3q to each side

4/3q+r=4/3p

Multiply ALL variables by 3/4 (undoes the 4/3)

q+3/4r=p

6 0

3 years ago