Answer:
is outside the circle of radius of 
centered at 
.
Step-by-step explanation:
Let 
and 
denote the center and the radius of this circle, respectively. Let 
be a point in the plane.
Let 
denote the Euclidean distance between point and point .
In other words, if is at 
while is at 
, then 
.
Point would be inside this circle if 
. (In other words, the distance between 
and the center of this circle is smaller than the radius of this circle.)
Point would be on this circle if 
. (In other words, the distance between and the center of this circle is exactly equal to the radius of this circle.)
Point would be outside this circle if 
. (In other words, the distance between and the center of this circle exceeds the radius of this circle.)
Calculate the actual distance between and :
.
On the other hand, notice that the radius of this circle, 
, is smaller than . Therefore, point would be outside this circle.
Move all terms that don't contain x to the right side and solve.
x=−5/3−y/3
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Trigonometric functions which are related by having the same value at complementary angles are called cofunctions. Cofunctions of complementary angles are equal.
A. csc 20' = csc(90-70)=sec 70
B. cos 87' = cos (90-3)=sin 3'
C. csc 40' = csc(90-50) =sec50'
D. tan 15' = tan(90-75)= cot 75'
Among all the option c is not correct.
Option C is false.
The answer will be 15-4=11
Add it tighter and it will make ur number then subtract that
