Since triangle ABC is similar to triangle DEF then the ratio of the corresponding sides is constant.
The ratio of the corresponding lengths is referred to as the linear scale factor.
Considering the heights of the two triangles;
L.S.F = 14/6
= 7/3
The ratio in area (A.S.F) is given by (L.S.F)²
Therefore, A.S.F = (7/3)² = 49/9
Thus te ratio of the area of triangle ABC to DEF is 49:9
<h2>~<u>Solution</u> :-</h2>
If we take the radius of a circle be <u>R</u>. Then, we can define that,
$ R = x $
Hence,
Arcs will be as $ 4x $. As,
A circle can be divided into four parts according to the radius.
Hence, we know that,


- Hence, <em>according to the radius R</em>, a circle can have <u>4 arcs</u>.
Answer:
θ = {(4/3 +2k)π, (5/3 +2k)π}
Step-by-step explanation:
From your knowledge of trig functions, you know that sin(60°) = sin(π/3) = (√3)/2. So, the angles of interest are in the 3rd- and 4th-quadrant and will have π/3 as their reference angle.
θ = 4/3π +2kπ, and 5/3π +2kπ